java - 带有 HashMap 的 ListView 只显示一个数据

Question

我提到了 this来自 androidhive 的网站，用于使用 HashMap 执行我的 ListView。我从数据库中获取数据没有问题，但我的 ListView 只能显示表的第一条记录。我不知道问题是在数据库中还是我没有在主要 Activity 中申请循环。如果是，我该如何应用它。请帮我!谢谢!

这是我获取数据的数据库

public ArrayList<Object> getFood(String cID)
{
    ArrayList<Object> rowArray = new ArrayList<Object>();
    Cursor cursor;

    try
    {
        String sql = "SELECT foodName, price FROM food_table WHERE categoryID = ?";
        cursor = db.rawQuery (sql, new String[]{""+cID});

        cursor.moveToFirst();

        if (!cursor.isAfterLast())
        {
            do
            {
                rowArray.add(cursor.getString(0));
                rowArray.add(cursor.getString(1));
            }
            while (cursor.moveToNext());
        }
        cursor.close();
    }

    catch (SQLException e)
    {
        Log.e("LIST ERROR", e.toString());
        e.printStackTrace();
    }
    return rowArray;
}

这是我的适配器

public class List2Adapter extends BaseAdapter {
private Activity activity;
private ArrayList<HashMap<String, String>> data;
private static LayoutInflater inflater=null;

public List2Adapter(Activity a, ArrayList<HashMap<String, String>> d)
{
    activity = a;
    data = d;
    inflater = (LayoutInflater)activity.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
}

@Override
public int getCount() {
    return data.size();
}

@Override
public Object getItem(int position) {
    return position;
}

@Override
public long getItemId(int position) {
    return position;
}

@Override
public View getView(int position, View convertView, ViewGroup parent)
{
    View vi = convertView;
    if (convertView == null)
    {
        vi = inflater.inflate(R.layout.row, null);
    }

    TextView foodname2 = (TextView)vi.findViewById(R.id.foodName2);
    TextView price = (TextView)vi.findViewById(R.id.price);

    HashMap<String,String> food = new HashMap<String, String>();
    food = data.get(position);

    foodname2.setText(food.get(MainActivity.FOODNAME2));
    price.setText(food.get(MainActivity.PRICE));

    return vi;
}
}

这是我的主要 Activity

static final String FOODNAME2 = "foodName";
static final String PRICE = "price";
private void listMenu(String CID)
{
    LISTORDER = (ListView) findViewById(R.id.listOrder);

    ArrayList<Object> data = DB.getFood(CID);

    ArrayList<HashMap<String, String>> test = new ArrayList<HashMap<String, String>>();

    HashMap<String, String> map = new HashMap<String, String>();

    map.put(FOODNAME2, (String) data.get(0));
    map.put(PRICE, (String) data.get(1));

    test.add(map);

    LISTMENU = (ListView) findViewById(R.id.listMenu);

    List2Adapter adapter = new List2Adapter(MainActivity.this, test);
    LISTMENU.setAdapter(adapter);}

Answer 1

这是因为您只添加了一项。更新您的 listMenu 方法:

private void listMenu(String CID)
{
    LISTORDER = (ListView) findViewById(R.id.listOrder);

    ArrayList<Object> data = DB.getFood(CID);
    ArrayList<HashMap<String, String>> test = new ArrayList<HashMap<String, String>>();

    for (int i=0;i<data.size();i=i+2) {
        HashMap<String, String> map = new HashMap<String, String>();
        map.put(FOODNAME2, (String) data.get(i));
        map.put(PRICE, (String) data.get(i+1));
        test.add(map);
    }

    LISTMENU = (ListView) findViewById(R.id.listMenu);

    List2Adapter adapter = new List2Adapter(MainActivity.this, test);
    LISTMENU.setAdapter(adapter);
}