android - 我想做一个法典应用程序

Question

我添加了 EditText.. 我在其中输入一个词，例如:power。之后我按下一个按钮，我希望每个字母都被改变......当我的意思是改变我的意思是这样...... A = d，B = e，C = f ..等等......我怎么能去做？ 这是我试过的..

public class MainActivity extends ActionBarActivity {
TextView myText, myText2, myText3, myText4;
Button myButton;
EditText myEditText1, myEditText2, myEditText3;
public String getText;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    myText = (TextView) findViewById(R.id.textView1);
    myText2 = (TextView) findViewById(R.id.textView2);
    myText3 = (TextView) findViewById(R.id.textView3);
    myText4 = (TextView) findViewById(R.id.textView4);

    myButton = (Button) findViewById(R.id.button1);
    myEditText1 = (EditText) findViewById(R.id.editText1);
    myEditText2 = (EditText) findViewById(R.id.editText2);
    myEditText3 = (EditText) findViewById(R.id.editText3);


    onClick();


}

public void onClick()
{
    myButton.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View view) {


            if (myEditText1.getText().toString().equals("a") || myEditText1.getText().toString().equals("A"))
            {
                myText.setText("X");
            }

            if (myEditText1.getText().toString().equals("b") || myEditText1.getText().toString().equals("B"))
            {
                myText.setText("Y");
            }

            if (myEditText1.getText().toString().equals("c") || myEditText1.getText().toString().equals("C"))
            {
                myText.setText("Z");
            }

            if (myEditText1.getText().toString().equals("d") || myEditText1.getText().toString().equals("D"))
            {
                myText.setText("A");
            }

            if (myEditText1.getText().toString().equals("e") || myEditText1.getText().toString().equals("E"))
            {
                myText.setText("B");
            }

            if (myEditText1.getText().toString().equals("f") || myEditText1.getText().toString().equals("F"))
            {
                myText.setText("C");
            }

            if (myEditText1.getText().toString().equals("g") || myEditText1.getText().toString().equals("G"))
            {
                myText.setText("D");
            }

            if (myEditText1.getText().toString().equals("h") || myEditText1.getText().toString().equals("H"))
            {
                myText.setText("E");
            }

            // EDIT TEXT 2

            if (myEditText2.getText().toString().equals("a") || myEditText2.getText().toString().equals("A"))
            {
                myText2.setText("X");
            }

            if (myEditText2.getText().toString().equals("b") || myEditText2.getText().toString().equals("B"))
            {
                myText2.setText("Y");
            }

            if (myEditText2.getText().toString().equals("c") || myEditText2.getText().toString().equals("C"))
            {
                myText2.setText("Z");
            }

            if (myEditText2.getText().toString().equals("d") || myEditText2.getText().toString().equals("D"))
            {
                myText2.setText("A");
            }

            if (myEditText2.getText().toString().equals("e") || myEditText2.getText().toString().equals("E"))
            {
                myText2.setText("B");
            }

            if (myEditText2.getText().toString().equals("f") || myEditText2.getText().toString().equals("F"))
            {
                myText2.setText("C");
            }

            if (myEditText2.getText().toString().equals("g") || myEditText2.getText().toString().equals("G"))
            {
                myText2.setText("D");
            }

            if (myEditText2.getText().toString().equals("h") || myEditText2.getText().toString().equals("H"))
            {
                myText2.setText("E");
            }

            // EDIT TEXT 3

            if (myEditText3.getText().toString().equals("a") || myEditText3.getText().toString().equals("A"))
            {
                myText3.setText("X");
            }

            if (myEditText3.getText().toString().equals("b") || myEditText3.getText().toString().equals("B"))
            {
                myText3.setText("Y");
            }

            if (myEditText3.getText().toString().equals("c") || myEditText3.getText().toString().equals("C"))
            {
                myText3.setText("Z");
            }

            if (myEditText3.getText().toString().equals("d") || myEditText3.getText().toString().equals("D"))
            {
                myText3.setText("A");
            }

            if (myEditText3.getText().toString().equals("e") || myEditText3.getText().toString().equals("E"))
            {
                myText3.setText("B");
            }

            if (myEditText3.getText().toString().equals("f") || myEditText3.getText().toString().equals("F"))
            {
                myText3.setText("C");
            }

            if (myEditText3.getText().toString().equals("g") || myEditText3.getText().toString().equals("G"))
            {
                myText3.setText("D");
            }

            if (myEditText3.getText().toString().equals("h") || myEditText3.getText().toString().equals("H"))
            {
                myText3.setText("E");
            }

        }
    });
}

Answer 1

这里是凯撒密码实现的例子:Java, How to implement a Shift Cipher (Caesar Cipher) .只需从编辑文本中读取值并调用函数来加密文本。

在你的情况下，你应该做这样的事情:

private void cipher(){
  int shift = 2;
  String msg = myEditTegt.getText();
  String s = "";
  int len = msg.length();
   for(int x = 0; x < len; x++){
    char c = (char)(msg.charAt(x) + shift);
    if (c > 'z')
        s += (char)(msg.charAt(x) - (26-shift));
    else
        s += (char)(msg.charAt(x) + shift);
   }
  myEditText.setText(s);
}

并在按下按钮时执行此方法。