我在使用 post 方法上传图像文件和字符串时遇到问题。该图像文件实际上确实上传到服务器，但我尝试用它发送一个字符串(用户名)失败了。我知道我得到了用户名的值，因为它在我调试时在日志中显示了用户名。任何想法都是为什么这不起作用。这是 doInbackground
protected String doInBackground(String... arg0) {
try {
String thePic = (String) arg0[0];
String name = (String) arg0[1];
String sourceFileUri = thePic;
Log.d("THENAME",name);
Log.d("Pic", thePic);
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
File sourceFile = new File(sourceFileUri);
if (sourceFile.isFile())
{
Log.d("CheckFile", "Its a file");
try {
String upLoadServerUri = "http://*Myaddress*.com/upload.php";
// open a URL connection to the Servlet
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE","multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("fileToUpload", sourceFileUri);
conn.setRequestProperty("Uname", name);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"fileToUpload\";filename=\"" + sourceFileUri + "\"" + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"Uname\"" + lineEnd);
dos.writeBytes(lineEnd);
String s = Integer.toString(dos.size());
Log.d("DOSFILESIZE", s);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0,bufferSize);
}
// send multipart form data necesssary after file
// data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn.getResponseMessage();
if (serverResponseCode == 200)
{
Log.d("Server Response",serverResponseMessage);
// messageText.setText(serverResponseMessage);
//Toast.makeText(this, "File Upload Complete.",Toast.LENGTH_SHORT).show();
//recursiveDelete(mDirectory1);
}
// close the streams //
fileInputStream.close();
dos.flush();
dos.close();
}
catch (Exception e)
{
//dialog.dismiss();
e.printStackTrace();
//messageText.setText("Got Exception : see logcat ");
//Toast.makeText(UploadToServer.this, "Got Exception : see logcat ",Toast.LENGTH_SHORT).show();
Log.e("Upload file to server Exception", "Exception : "+ e.getMessage(), e);
}
// dialog.dismiss();
} // End else block
else
{
Log.d("No image", "Source is not an iamge file");
}
} catch (Exception ex) {
// dialog.dismiss();
ex.printStackTrace();
}
return "Executed";
}
这是php代码
<?php
$myfile = fopen("userlog.txt", "a");
fwrite($myfile, "\n\n\n\r\r\n");
fwrite($myfile, "\n\n\n\r\r\n");
fwrite($myfile, date("F j, Y, g:i a") . "\r");
fwrite($myfile, $_SERVER['REMOTE_ADDR']);
fclose($myfile);
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
$Uname = $_POST["Uname"];
$status1 = False;
$status2 = False;
$check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
if($check !== false) {
$uploadOk = 1;
$con = $con = mysql_connect("localhost:3036","username","password");
if
(!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("Rate_It", $con);
$imgData = file_get_contents($_FILES["fileToUpload"]["tmp_name"]);
$zero = 0;
$pid = "NULL";
$name = "car789";
$date = "CURDATE()";
$sql = sprintf("INSERT INTO Picture
(Pid, Uname, Image, Views, RateTotal, UploadName, UploadDate)
VALUES
('%s', '%s', '%s', '%d', '%d' ,'%s' ,%s)",
$pid,
$Uname,
mysql_real_escape_string($imgData),
$zero,
$zero,
$target_file,
$date
);
$myfile = fopen("test.txt", "a");
fwrite($myfile, "\n\n\n\r\r\n");
fwrite($myfile, "\n\n\n\r\r\n");
fwrite($myfile, date("F j, Y, g:i a"));
fwrite($myfile, "$sql\n");
fclose($myfile);
if ( mysql_query($sql) == TRUE) {
$status1 = True;
}
else {
$status1 = False;
}
mysql_close($con);
} else {
$uploadOk = 0;
}
if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
$status2 = True;
} else {
$status2 = False;
}
if($status1 == True && $status2 == True){
echo "True";
}
else{
echo "False";
}
?>
最佳答案
紧接着
dos = new DataOutputStream(conn.getOutputStream());
添加以下代码:
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"Uname\"" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(name + lineEnd);
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"thepic\"" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(thePic + lineEnd);
删除所有带有 `Uname 的行，因为那行不通。
另外，为了抓取 php 脚本回显的页面，在 try block 的末尾添加以下代码:
InputStream in = new BufferedInputStream(conn.getInputStream());
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder sb = new StringBuilder();
String newLine = System.getProperty("line.separator");
String line;
while ((line = reader.readLine()) != null) {
sb.append(line + newLine);
}
String resultPage = sb.toString();
查看您的 php 脚本，您将收到的信息不多。只有“真”或“假”；
`
关于php - 使用android和post方法将图像文件和字符串上传到php后端，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/29930404/