java - Android-通过异常解析Json

Question

Android-

我收到以下 JSON 响应。单击特定 ID(1,1015,1016，见下文)时，我有按钮。它将返回内部 Json 对象。

我只在获取特定 IDs(Json) 时遇到问题

[
        {
            "1":
            [
                {
                    "a": "a",
                    "b": 1,
                    "c": "1",
                    "d": "1-1-1-1"
                },
                {
                    "a": "a",
                    "b": 6,
                    "c": "2",
                    "d": "1-1-1",
                    "e": "Meals"
                }
            ]
        },
        {
            "1015":
            [
            ]
        },
        {
            "1016":
            [
                {
                    "a": "a",
                    "b": 6,
                    "c": "2",
                    "d": "1-1-1",
                    "e": "Meals1234"
                }
            ]
        },
        {
            "1012":
            [
                {
                    "a": "venky",
                    "b": 6,
                    "c": "2",
                    "d": "1-1-1",
                    "e": "Meals"
                },
                {
                    "a": "venky2",
                    "b": 45,
                    "c": "2",
                    "d": "1-1-1",
                    "e": "Meals"
                }
            ]
        },
        {
            "1011":
            [
                {
                   "a": "a",
                    "b": 6,
                    "c": "2",
                    "d": "1-1-1",
                    "e": "Meals567"
                },
                {
                    "a": "a",
                    "b": 6,
                    "c": "2",
                    "d": "1-1-1",
                    "e": "Meals08676"
                }
            ]
        }
    ]

我写的JSON解析的Java代码如下

public void load_whole_JsonData() {
        String number = ET_number.getText().toString().trim(); // edittext number is 1 (for example)
        JSONArray jsonArray1;
        JSONObject obj1; 
        JSONArray jsonArray2;
        try {
            jsonArray1=new JSONArray(JsonResponse); // parse the Json response here
            obj1=new JSONObject();
            for (int i = 0; i < jsonArray1.length(); i++) {
                try {
                    jsonArray2= jsonArray1.getJSONObject(i).getJSONArray(number); //number is IDs :  1 , 1015,1016 
                    Log.v("test", "i"+i+ " obj1 "+jsonArray2);
                }
                catch (Exception e){
                    Log.v("test", "exception "+e);
                }
            }

        } catch (JSONException e) {
            Log.v("MTV", "JsonParser exception" + e);
            e.printStackTrace();
        }
    }

我得到了正确的输出但是 Catch 抛出是因为

jsonArray2 = jsonArray1.getJSONObject(i).getJSONArray(number); //number is IDs :  1 , 1015,1016 

输出(在 Logcat 中):

 V/test: i0 obj1 [{"a":"a","b":1,"c":"1","d":"1-1-1-1","e":"Meals"},{"a":"a","b":6,"c":"2","d":"1-1-1","e":"Meals"}] //This is the output

 V/test: exception org.json.JSONException: No value for 1 //catch exceptions
 V/test: exception org.json.JSONException: No value for 1
 V/test: exception org.json.JSONException: No value for 1
 V/test: exception org.json.JSONException: No value for 1

如果有人想在不捕获异常的情况下获得输出。 那么如何获取内部细节，如 [{"a":"a","b":1,"c ":"1","d":"1-1-1-1","e":"膳食"},{"a":"a","b":6,"c":"2 ","d":"1-1-1","e":"膳食"}]

已编辑:

如果我给出的数字是 1016。它只会解析 1016 [{"a":"a","b":1,"c":"1","d":"1 的内部细节-1-1-1","e":"Meals"}(从整个 JSON 响应中获取)

Answer 1

您的代码无法正常工作，因为在每个 JSONObject 中您都试图找到一个键为 1 的数组，但该数组不可用。因此，在每个 JSONObject 中，您需要使用与数组相关联的正确键。

这样做

try {
        jsonArray1=new JSONArray(JsonResponse); // parse the Json response here
        obj1=new JSONObject();
        for (int i = 0; i < jsonArray1.length(); i++) {
            try {
                    JSONObject innerJson = jsonArray1.getJSONObject(i);
                    for(Iterator<String> iter = innerJson.keys();iter.hasNext();) 
                    {
                        String key = iter.next();
                        jsonArray2 = innerJson.getJSONArray(key);
                    }
                Log.v("test", "i"+i+ " obj1 "+jsonArray2);
            }
            catch (Exception e){
                Log.v("test", "exception "+e);
            }
        }

    } catch (JSONException e) {
        Log.v("MTV", "JsonParser exception" + e);
        e.printStackTrace();
    }

更新

try {
        jsonArray1=new JSONArray(JsonResponse); // parse the Json response here
        obj1=new JSONObject();
        for (int i = 0; i < jsonArray1.length(); i++) {
            try {
                    JSONObject innerJson = jsonArray1.getJSONObject(i);
                    for(Iterator<String> iter = innerJson.keys();iter.hasNext();) 
                    {
                        String key = iter.next();
                        if(!key.equalIgnoreCase(myKey)) // myKey is the key you want to parse such as 1016
                            continue;
                        jsonArray2 = innerJson.getJSONArray(key);
                    }
                Log.v("test", "i"+i+ " obj1 "+jsonArray2);
            }
            catch (Exception e){
                Log.v("test", "exception "+e);
            }
        }

    } catch (JSONException e) {
        Log.v("MTV", "JsonParser exception" + e);
        e.printStackTrace();
    }