我有一个应用程序,当我们点击一个按钮时,该应用程序会启动带有搜索查询的谷歌地图。但我需要打开位置才能提供准确的结果。可能吗?
最佳答案
我明白你的问题 这是应该添加到您的 onCreate 方法中的代码
LocationManager lm = (LocationManager) getSystemService(LOCATION_SERVICE);
if (!lm.isProviderEnabled(LocationManager.GPS_PROVIDER) ||
!lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER)) {
// Build the alert dialog
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setTitle("Location Services Not Active");
builder.setMessage("Please enable Location Services and GPS");
builder.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialogInterface, int i) {
// Show location settings when the user acknowledges the alert dialog
Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
startActivity(intent);
}
});
Dialog alertDialog = builder.create();
alertDialog.setCanceledOnTouchOutside(false);
alertDialog.show();
}
关于android - 如何提示用户打开位置?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36681528/