因此,我必须使用 ListView 编写一个应用程序。它必须起作用:您正在单击项目,它会引导您进入第二个 Activity 。必须有来自 JSON 的信息。我是用 okHttp 做的。我离我的命运不远了,但这是一个错误。 已解决。 下一个问题:点击ListView item没有反应。
MainActivity.java(部分问题代码):
public class MainActivity extends AppCompatActivity {
private ListView listView;
private ArrayList<String> list = new ArrayList<>();
private ArrayAdapter<String> adapter;
private List<MyDataModel> datas = new ArrayList<>();
public class MyClickListener implements AdapterView.OnItemClickListener{
List<MyDataModel> datas;
public MyClickListener(List<MyDataModel> datas){
this.datas = datas;
}
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id){
Intent intent = new Intent(MainActivity.this, DetailsActivity.class);
if(position < datas.size()){
MyDataModel data = datas.get(position);
intent.putExtra(Key.KEY_ID,data.getItemId());
intent.putExtra(Key.KEY_ABOUT,data.getAbout());
intent.putExtra(Key.KEY_ADDRESS,data.getAddress());
intent.putExtra(Key.KEY_COMPANY,data.getCompany());
intent.putExtra(Key.KEY_EMAIL,data.getEmail());
intent.putExtra(Key.KEY_FIRST_NAME,data.getFirstName());
intent.putExtra(Key.KEY_LAST_NAME,data.getLastName());
intent.putExtra(Key.KEY_PHONE,data.getPhone());
}
datas.add(new MyDataModel());
}
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
list = new ArrayList<String>();
adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, android.R.id.text1, list);
listView = (ListView) findViewById(R.id.listView);
listView.setAdapter(adapter);
listView.setOnItemClickListener(new MyClickListener(datas));
以及DetailsActivity.java的代码:
public class DetailsActivity extends AppCompatActivity{
private TextView textViewId;
private TextView textViewAbout;
private TextView textViewAddress;
private TextView textViewCompany;
private TextView textViewEmail;
private TextView textViewFirstName;
private TextView textViewLastName;
private TextView textViewPhone;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_details);
textViewId = (TextView) findViewById(R.id.textViewId);
textViewAbout = (TextView) findViewById(R.id.textViewAbout);
textViewAddress = (TextView) findViewById(R.id.textViewAddress);
textViewCompany = (TextView) findViewById(R.id.textViewCompany);
textViewEmail = (TextView) findViewById(R.id.textViewEmail);
textViewFirstName = (TextView) findViewById(R.id.textViewFirstName);
textViewLastName = (TextView) findViewById(R.id.textViewLastName);
textViewPhone = (TextView) findViewById(R.id.textViewPhone);
Intent intent = getIntent();
textViewId.setText(String.valueOf(intent.getIntExtra(Key.KEY_ID, 0)));
textViewAbout.setText(intent.getStringExtra(Key.KEY_ABOUT));
textViewAddress.setText(intent.getStringExtra(Key.KEY_ADDRESS));
textViewCompany.setText(intent.getStringExtra(Key.KEY_COMPANY));
textViewEmail.setText(intent.getStringExtra(Key.KEY_EMAIL));
textViewFirstName.setText(intent.getStringExtra(Key.KEY_FIRST_NAME));
textViewLastName.setText(intent.getStringExtra(Key.KEY_LAST_NAME));
textViewPhone.setText(intent.getStringExtra(Key.KEY_PHONE));
}
}
我认为给你 MyDataModel.java 会很有用:
public class MyDataModel {
private String about;
private String address;
private String company;
private String email;
private String firstname;
private String lastname;
private String phone;
private int itemId;
private String photo;
public String getAbout(){
return about;
}
public void setAbout(String about){
this.about = about;
}
public String getAddress(){
return address;
}
public void setAddress(String address){
this.address = address;
}
public String getEmail(){
return email;
}
public void setEmail(String email){
this.email = email;
}
public String getFirstName(){
return firstname;
}
public void setFirstName(String firstname){
this.firstname = firstname;
}
public String getCompany(){
return company;
}
public void setCompany(String company){
this.company = company;
}
public String getLastName(){
return lastname;
}
public void setLastName(String lastname){
this.lastname = lastname;
}
public String getPhone(){
return phone;
}
public void setPhone(String phone){
this.phone = phone;
}
public int getItemId(){
return itemId;
}
public void setItemId(int itemId){
this.itemId = itemId;
}
public String getPhoto(){
return photo;
}
public void setPhoto(String photo){
this.photo = photo;
}
}
最佳答案
当你得到一个 java.lang.IndexOutOfBoundsException
意味着你正试图访问你的数据结构中一个不存在的索引,在这个例子中是索引 1,当总大小为 0 时(索引: 1, 大小: 0)
来自official Java documentation :
public class IndexOutOfBoundsException extends RuntimeException
Thrown to indicate that an index of some sort (such as to an array, to a string, or to a vector) is out of range.
建议:首先定义监听器,将列表引用传递给构造函数,这样当用户单击时,您可以检查它是否为空
public class MyClickListener implements AdapterView.OnItemClickListener{
List<MyDataModel> datas;
public MyClickListener(List<MyDataModel> datas)
{
this.datas = datas;
}
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
Intent intent = new Intent(MainActivity.this, DetailsActivity.class);
//--> this was a problem--> datas = new ArrayList<MyDataModel>();
if (position < datas.size())
{
MyDataModel data = datas.get(position);
intent.putExtra(Key.KEY_ID,data.getItemId());
intent.putExtra(Key.KEY_ABOUT,data.getAbout());
intent.putExtra(Key.KEY_ADDRESS,data.getAddress());
intent.putExtra(Key.KEY_COMPANY,data.getCompany());
intent.putExtra(Key.KEY_EMAIL,data.getEmail());
intent.putExtra(Key.KEY_FIRST_NAME,data.getFirstName());
intent.putExtra(Key.KEY_LAST_NAME,data.getLastName());
intent.putExtra(Key.KEY_PHONE,data.getPhone());
view.getContext().startActivity(intent);
}
}
然后在你想要的地方设置监听器
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
//...
listView.setOnItemClickListener(new MyClickListener(datas));
//...
关于java - 数组列表 java 错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40129697/