android - 无法从 ListView 获取选定的项目文本

Question

我只是想在用户单击的行的 ListView 中显示文本。

ListView 和适配器

ListView listCurrent = (ListView)findViewById(R.id.currentlinkslist);

    try {
        SQLiteOpenHelper tractionDatabaseHelper = new TractionDatabaseHelper(this);
        db = tractionDatabaseHelper.getReadableDatabase();
        String query = "SELECT _id, QUESTION FROM QUESTION";

        cursor = db.rawQuery(query, null);

        CursorAdapter listAdapter = new SimpleCursorAdapter(this,
                android.R.layout.simple_list_item_1,
                cursor,
                new String[]{"QUESTION"},
                new int[]{android.R.id.text1},0);

        listCurrent.setAdapter(listAdapter);

    }catch(SQLiteException e) {
        Toast.makeText(this, "Database unavailable", Toast.LENGTH_SHORT).show();
    }


    AdapterView.OnItemClickListener itemClickListener =
            new AdapterView.OnItemClickListener() {
                public void onItemClick(AdapterView<?> listCurrent,
                                        View v, int position, long id) {
                    String selectedItem = listCurrent.getItemAtPosition(position).toString();
                    Toast.makeText(AssociateActivity.this,
                            selectedItem , Toast.LENGTH_SHORT).show();

                }
            };

    listCurrent.setOnItemClickListener(itemClickListener);

从我所看到的一切来看，AdapterView.OnItemClickListener 中的这段代码应该获取描述:

String selectedItem = listCurrent.getItemAtPosition(position).toString();
Toast.makeText(AssociateActivity.this, selectedItem, Toast.LENGTH_SHORT).show();

相反，我不断得到:

我做错了什么？

Answer 1

方法 getItemAtPosition() 返回一个 SQLiteCursor 对象，这种对象没有方法 toString() 的实现。所以在这种情况下，您必须返回游标本身并将其解析为您的对象，然后再调用 toString() 方法。

SQLiteCursor cursor = (SQLiteCursor) listCurrent.getItemAtPosition(position);
 String selectedItem = cursor.getString(columIndex); //columIndex is not the position

Toast.makeText(AssociateActivity.this, selectedItem, Toast.LENGTH_SHORT).show();