这是我的 Android 代码:
public void SendDataToServer(final String name, final String email, final String password){
class SendPostReqAsyncTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
String QuickName = name ;
String QuickEmail = email ;
String QuickPassword = password;
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("nome", QuickName));
nameValuePairs.add(new BasicNameValuePair("email", QuickEmail));
nameValuePairs.add(new BasicNameValuePair("password", QuickPassword));
try {
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(Configs.signup);
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpClient.execute(httpPost);
HttpEntity entity = response.getEntity();
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
return "Data Submit Successfully";
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
Log.d(result, "Value");
try {
JSONObject jo = new JSONObject(result);
String status = jo.optString("status");
if (status.equals("0")) {
Toast.makeText(Signup.this, "Username already exists", Toast.LENGTH_LONG).show();
} else if (status.equals("1")) {
Intent intent = new Intent(Signup.this, Login.class);
startActivity(intent);
Toast.makeText(Signup.this, "Registered successfully", Toast.LENGTH_LONG).show();
Toast.makeText(Signup.this, "Verify your email adress in email received", Toast.LENGTH_SHORT).show();
finish();
} else if (status.equals("2")) {
Toast.makeText(Signup.this, "Failed to Signup", Toast.LENGTH_LONG).show();
}
//}
}catch (JSONException e) {
e.printStackTrace();
}
}
}
SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
sendPostReqAsyncTask.execute(name, email, password);
}
这是错误:
07-21 12:55:35.297 24973-24973/com.futegolo.igomessenger W/System.err: org.json.JSONException: Value Data of type java.lang.String cannot be converted to JSONObject
这是我的 json 响应
{"status":0}
最佳答案
这是因为您没有在 doInBackground() 方法中返回来自服务的实际响应。你回来了
return "Data Submit Successfully"
当您在 onPostExecute() 方法中转换该字符串时，显然这不是有效的 JsonObject
在此“HttpEntity entity = response.getEntity();”之后替换您的代码
HttpEntity entity = response.getEntity();
String result = null;
if (entity != null) {
// A Simple JSON Response Read
InputStream instream = entity.getContent();
result= convertStreamToString(instream);
// now you have the string representation of the HTML request
instream.close();
}
private static String convertStreamToString(InputStream is) {
/*
* To convert the InputStream to String we use the BufferedReader.readLine()
* method. We iterate until the BufferedReader return null which means
* there's no more data to read. Each line will appended to a StringBuilder
* and returned as String.
*/
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try {
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
而是返回您的硬编码字符串返回结果。希望有所帮助。 如需进一步引用，您可以点击以下链接
https://stackoverflow.com/questions/4457492/how-do-i-use-the-simple-http-client-in-android
关于java - org.json.JSONException : Value Data of type java. lang.String 无法转换为 JSONObject，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/45237105/