我有需要用户 ID 才能连接的套接字服务器。因此,我需要将 extraHeader 设置为连接构造函数。我尝试了以下代码,但没有运气。请帮我解决这个问题,谢谢。
向连接构造函数添加额外 header 'x-user-id': userId
private Socket mSocket;
{
try {
IO.Options opts = new IO.Options();
mSocket = IO.socket(socket_url, opts);
mSocket.io().on(Manager.EVENT_TRANSPORT, new Emitter.Listener() {
@Override
public void call(Object... args) {
Transport transport = (Transport)args[0];
transport.on(Transport.EVENT_REQUEST_HEADERS, new Emitter.Listener() {
@Override
public void call(Object... args) {
@SuppressWarnings("unchecked")
Map<String, List<String>> headers = (Map<String, List<String>>)args[0];
// modify request headers
headers.put("x-user-id", Arrays.asList("5B59F68B7B7811E88C3E52964BF487E4"));
}
}).on(Transport.EVENT_RESPONSE_HEADERS, new Emitter.Listener() {
@Override
public void call(Object... args) {
}
});
}
});
} catch (URISyntaxException e) {}
}
这是我的有效代码。
private init(){
self.socketManager = SocketManager(socketURL: URL(string:"\(MAIN_URL)/message")!, config: [.log(true),.extraHeaders(["x-user-id":AppManager.instance.userId])])
self.socket = socketManager?.defaultSocket
}
最佳答案
您还可以使用Spring框架提供的stomp客户端。 要编译并运行以下方法,您应该将“spring-messaging”和“spring-websocket”maven 依赖项添加到您的项目中。
public ListenableFuture<StompSession> connect() {
List<Transport> transports = new ArrayList<>(2);
transports.add(new WebSocketTransport(new StandardWebSocketClient()));
transports.add(new RestTemplateXhrTransport());
SockJsClient sockJsClient = new SockJsClient(transports);
sockJsClient.setMessageCodec(new Jackson2SockJsMessageCodec());
WebSocketStompClient stompClient = new WebSocketStompClient(sockJsClient);
stompClient.setMessageConverter(new MappingJackson2MessageConverter());
WebSocketHttpHeaders headers = new WebSocketHttpHeaders();
headers.add("x-user-id", "5B59F68B7B7811E88C3E52964BF487E4");
return stompClient.connect(socket_url, headers, new StompSessionHandlerAdapter() {});
}
关于android - 带 header 的 Socket.IO-client Java,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51120178/