当我在 GridView
中来回滚动时,我的图像没有正确回收,最终将在整个网格中显示相同的图像。
适配器
public class ImageAdapter extends BaseAdapter {
private Context mContext;
private List<String> mList;
private int mheight;
private int mwidth;
private Bitmap nBitmap;
public ImageAdapter(Context context, List<String> list, int height, int width) {
mContext = context;
mList = list;
mheight = height;
mwidth = width;
}
@Override
public int getCount() {
return mList.size();
}
@Override
public Object getItem(int position) {
return mList.get(position).toString();
}
@Override
public long getItemId(int position) {
return 0;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
ImageView imageView;
if (convertView == null) {
imageView = new ImageView(mContext);
InputStream is;
try {
is = mContext.getAssets().open(mList.get(position));
Bitmap bm = BitmapFactory.decodeStream(is);
Bitmap mBitmap = Bitmap.createScaledBitmap(bm, mwidth / 3, mwidth / 3, false);
imageView.setScaleType(ImageView.ScaleType.CENTER_CROP);
this.nBitmap = mBitmap;
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
} else {
imageView = (ImageView) convertView;
}
imageView.setImageBitmap(nBitmap);
return imageView;
}
}
我试图从快速滚动的 Ui 线程解码位图,但启动应用程序时缩略图被 1 个 1 加载,回收的缩略图 View 从原始 View 更改,在低内存设备上应用程序崩溃,同时从此处的 AsyncTask 加载缩略图已更新代码
public class ImageAdapter extends BaseAdapter {
private Context mContext;
private List<String> mList;
private int mheight;
private int mwidth;
private InputStream is;
public ImageAdapter(Context context, List<String> list, int height, int width) {
mContext = context;
mList = list;
mheight = height;
mwidth = width;
}
@Override
public int getCount() {
return mList.size();
}
@Override
public Object getItem(int position) {
return mList.get(position).toString();
}
@Override
public long getItemId(int position) {
return 0;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
ImageView imageView;
if (convertView == null) {
imageView = new ImageView(mContext);
} else {
imageView = (ImageView) convertView;
}
InputStream is;
try {
is = mContext.getAssets().open(mList.get(position));
Loadimage task = new Loadimage(imageView , mheight , mwidth);
task.execute(is);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return imageView ;
}
public class Loadimage extends AsyncTask<InputStream, Void, Bitmap>{
private final WeakReference<ImageView> imageViewReference;
private InputStream is = null;
private int width;
public Loadimage(ImageView imageView, int mheight, int mwidth) {
imageViewReference = new WeakReference<ImageView>(imageView);
this.width=mwidth;
// TODO Auto-generated constructor stub
}
@Override
protected Bitmap doInBackground(InputStream... params) {
is = params[0];
if (is !=null) {
Bitmap bitmap = BitmapFactory.decodeStream(is);
Bitmap nBitmap =Bitmap.createScaledBitmap(bitmap,width/3 , width/3, false);
return nBitmap;
}
return null;
}
@Override
protected void onPostExecute(Bitmap bitmap) {
if (imageViewReference != null && bitmap != null) {
final ImageView imageView = imageViewReference.get();
if (imageView != null) {
imageView.setImageBitmap(bitmap);
imageView.setScaleType(ImageView.ScaleType.CENTER_CROP);
}
}
最佳答案
您需要将生成位图的 block 移到 if/then
之外。现在,您仅在 convertView == null
时生成新的位图。
我相信您的代码是正确的:
public class ImageAdapter extends BaseAdapter {
private Context mContext;
private List<String> mList;
private int mheight;
private int mwidth;
public ImageAdapter(Context context, List<String> list, int height, int width) {
mContext = context;
mList = list;
mheight = height;
mwidth = width;
}
@Override
public int getCount() {
return mList.size();
}
@Override
public Object getItem(int position) {
return mList.get(position).toString();
}
@Override
public long getItemId(int position) {
return 0;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
ImageView imageView;
if (convertView == null) {
imageView = new ImageView(mContext);
} else {
imageView = (ImageView) convertView;
}
InputStream is;
try {
is = mContext.getAssets().open(mList.get(position));
Bitmap bm = BitmapFactory.decodeStream(is);
Bitmap bitmap = Bitmap.createScaledBitmap(bm, mwidth / 3, mwidth / 3, false);
imageView.setScaleType(ImageView.ScaleType.CENTER_CROP);
imageView.setImageBitmap(bitmap);
} catch (IOException e) {
e.printStackTrace();
}
return imageView;
}
}
你的滚动不会很流畅,你会得到很多丢帧,因为你的位图解码代码效率低下(没有缓存),而且这一切都发生在 UI 线程上,这不利于响应。当前代码中的瓶颈不是 ImageView
的分配和垃圾收集。
瓶颈(可能到目前为止)是您对 Bitmap
的处理和创建。
您可以查看以下链接以获取建议:
Displaying Bitmaps Efficiently
特别是这个:
关于android - 异步任务的 Gridview 回收问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15560008/