我想ZIP
大文件,大约500MB
或超过1GB
。我使用过 AsyncTask
,但它不适用于这么大的文件。
这么长的任务我该怎么办?我还想用 p进度条
更新 UI
,我该怎么做?
最佳答案
I want to ZIP files which are large, around 500MB or over 1GB also. I have used AsyncTask, but it doesn't work with such large files.
AsyncTask 不是为长任务指定的,而是为只能持续几秒钟的任务指定的。
What should I do, to handle such long tasks? I also want to update the UI with a progress bar, how can I do that?
对于长任务通常使用IntentService这也是为此目的直接指定的,但它无法通过其 native 实现方式提供如何与 UI 线程通信。
要解决此问题,您可以使用 ResultReceiver您可以通过 Intent 传递到 IntentService,然后它应该可以工作。
快速基础教程:
如何创建IntentService:
public class Worker extends IntentService {
public static final int PROGRESS_UPDATE = 324;
public static final String PROGRESS = "progress";
@Override
protected void onHandleIntent(Intent intent) {
// Get data from Intent
ResultReceiver r = (ResultReceiver) intent.getParcelableExtra("key");
...
// do your work
...
// send update to caller Activity
Bundle data = new Bundle();
data.putExtra(Worker.PROGRESS, value);
r.send(Worker.PROGRESS_UPDATE, data);
...
}
}
如何创建 ResultReceiver(例如在您的调用者 Activity 中):
private class WorkerReceiver extends ResultReceiver {
public WorkerReceiver(Handler handler) {
super(handler);
}
@Override
public void onReceiveResult(int resultCode, Bundle resultData) {
super.onReceiveResult(resultCode, resultData);
if (resultCode == Worker.PROGRESS_UPDATE) {
int progress = resultData.getInt(Worker.PROGRESS);
// update your UI with current information from Worker
}
}
}
最后,如何执行IntentService:
Intent i = new Intent(this, Worker.class);
// put some extra data you want
i.putExtra("key", new WorkerReceiver(new Handler()));
...
startService(i);
最后不要忘记将您的 IntentService 添加到 Manifest.xml1
<service
android:name=".Worker"
>
// here you can also define intent-filter
</service>
希望能帮到您解决问题。
1否则您的 IntentService 永远不会被执行(即使您将启动它)。
关于android - Android 中的长时间运行任务,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24840828/