我有一个自定义的 volley 请求,但是在发送请求时它没有接受我的参数,我的代码有什么问题吗?
我在getParams
和getPostParams
下了断点,但是都没有通过。
我使用了 com.mcxiaoke.volley:library:1.0.+
,它是从 google volley 派生出来的以支持 maven。
我发现该类(class)在真实设备上运行良好,但无法在 genymotion 上运行。
public class GsonRequest<T> extends Request<T> {
private Class<T> clazz;
private Map<String, String> headers;
private Map<String, String> params;
private Listener<T> listener;
public GsonRequest(Api api, Class<T> clazz, Listener<T> listener, ErrorListener errorListener) {
this(api, clazz, null, null, listener, errorListener);
}
public GsonRequest(Api api, Class<T> clazz, Map<String, String> params, Listener<T> listener,
ErrorListener errorListener) {
this(api, clazz, params, null, listener, errorListener);
}
/**
* Make a GET request and return a parsed object from JSON.
*
* @param url
* URL of the request to make
* @param clazz
* Relevant class object, for Gson's reflection
* @param headers
* Map of request headers
*/
public GsonRequest(Api api, Class<T> clazz, Map<String, String> params, Map<String, String> headers,
Listener<T> listener, ErrorListener errorListener) {
super(api.method, api.url, errorListener);
this.clazz = clazz;
this.params = params;
this.headers = headers;
this.listener = listener;
}
// use new GsonRequest()
@Deprecated
public GsonRequest(String url, Class<T> clazz, Map<String, String> headers, Listener<T> listener,
ErrorListener errorListener) {
super(Method.GET, url, errorListener);
this.clazz = clazz;
this.headers = headers;
this.listener = listener;
}
@Override
public Map<String, String> getHeaders() throws AuthFailureError {
return headers != null ? headers : super.getHeaders();
}
@Override
public Map<String, String> getParams() throws AuthFailureError {
Map<String, String> result = params;
return result;
}
@Override
public Map<String, String> getPostParams() throws AuthFailureError {
Map<String, String> result = params;
return result;
}
@Override
protected void deliverResponse(T response) {
listener.onResponse(response);
}
@Override
protected Response<T> parseNetworkResponse(NetworkResponse response) {
try {
String json = new String(response.data, HttpHeaderParser.parseCharset(response.headers, "utf-8"));
// Log.d("zhch", json);
return Response.success(GsonUtils.fromJson(json, clazz), HttpHeaderParser.parseCacheHeaders(response));
} catch (UnsupportedEncodingException e) {
return Response.error(new ParseError(e));
} catch (JsonSyntaxException e) {
return Response.error(new ParseError(e));
}
}
}
最佳答案
此答案假定您正在尝试发出 GET 请求。
我遇到了类似的问题。在使用 Volley 传递参数时,GET 请求与 POST 请求略有不同。 当您发出 GET 请求时,传递参数的一种方法是在 url 字符串本身内部,这对我有用:
(这是一个部分示例,但应该为您提供修改自己的代码所需的大部分内容)
在发送请求的类中,我使用了一个小方法将参数附加到 url:
//this method sits somewhere in your class
private String createGetWithParams(String url, Map<String, Object> params)
{
StringBuilder builder = new StringBuilder();
for (String key : params.keySet())
{
Object value = params.get(key);
if (value != null)
{
try
{
value = URLEncoder.encode(String.valueOf(value), HTTP.UTF_8);
if (builder.length() > 0)
builder.append("&");
builder.append(key).append("=").append(value);
}
catch (UnsupportedEncodingException e)
{
}
}
}
return (url += "?" + builder.toString());
}
//this method sits somewhere in the same class, this fires the request
public void doSomeRequest()
{
Map<String, Object> jsonParams = new HashMap<>();
jsonParams.put("SomeParam", SomeParamValue);
jsonParams.put("SomeOtherParam", SomeOtherParamValue);
String url = createGetWithParams("some/request/url", jsonParams);
StringRequest request = new StringRequest(Request.Method.GET, url,
new Response.Listener<String>()
{
@Override
public void onResponse(String response)
{
// do whatever
}
},
new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error)
{
if (null != error.networkResponse)
{
Log.d(" Volley Error Response code: ", ""+ error.networkResponse.statusCode);
}
}
});
requestQueue.add(request);
我还创建了一个替换 StringRequest 的自定义请求类,但这是为了更好地控制解析响应 - 虽然可能对您有所帮助,但在此类中我只覆盖响应:
public class CustomStringRequest extends StringRequest
{
private final Response.Listener<String> mListener;
public CustomStringRequest(int method, String url, Response.Listener<String> listener, Response.ErrorListener errorListener)
{
super(method,url, listener, errorListener);
mListener = listener;
}
@Override
protected Response<String> parseNetworkResponse(NetworkResponse response)
{
try
{
// response.data is the byte array, do whatever..
String responseBody = new String(response.data, "utf-8");
Log.d(" NetworkResponse", responseBody);
return (Response.success(responseBody, getCacheEntry()));
}
catch (UnsupportedEncodingException e)
{
VolleyLog.e("UnsupportedEncodingException");
Log.d("NetworkResponse Exception", e.getMessage() );
return (null);
}
}
@Override
protected void deliverResponse(String response)
{
mListener.onResponse(response);
}
我知道的另一种方法是使用特定的 http 客户端,我没有用过这种方法,但您可能会使用 OkHttp 或类似的东西。
希望这对您有所帮助!
关于android - Volley 请求不带参数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29761634/