假设我有一个列表列表:
[[5, 10, 30, 24, 100], [1, 9, 25, 49, 81]]
[[15, 10, 10, 16, 70], [10, 1, 25, 11, 19]]
[[34, 20, 10, 10, 30], [9, 20, 25, 30, 80]]
现在我想要第一个列表的所有索引的总和,然后是第二个列表 5+15+34=54 10+10+20=40
等等:
[54,40,50, 50,200], [20,30,75,90,180]
我试过:
for res in results:
print [sum(j) for j in zip(*res)]
这里的 results
是列表的列表。
但它给出了每个列表项的总和:
[6,19,55,73,181]
[25,11,35,27,89]
[43,40,35,40,110]
最佳答案
你几乎是正确的,你需要解压 results
并压缩它。
>>> data = [[[5, 10, 30, 24, 100], [1, 9, 25, 49, 81]],
... [[15, 10, 10, 16, 70], [10, 1, 25, 11, 19]],
... [[34, 20, 10, 10, 30], [9, 20, 25, 30, 80]]]
>>> for res in zip(*data):
... print [sum(j) for j in zip(*res)]
...
[54, 40, 50, 50, 200]
[20, 30, 75, 90, 180]
你可以简单地用列表理解来写这个
>>> [[sum(item) for item in zip(*items)] for items in zip(*data)]
[[54, 40, 50, 50, 200], [20, 30, 75, 90, 180]]
关于python - 多个列表列表索引的总和,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36003967/