android - 如何使用 phonegap 在 Android 手机上显示摄像头

标签 android cordova camera

我想在 Android 手机上使用 phonegap 捕捉图像。我尝试了 Phonegap 页面上发布的代码,但没有出现相机。感谢您的帮助。非常感谢。

这是我手机上的显示

It is the display on my phone, there is no camera

<!DOCTYPE html>
<html>
  <head>
    <title>Capture Photo</title>

    <script type="text/javascript" charset="utf-8" src="cordova-1.6.0.js"></script>
    <script type="text/javascript" charset="utf-8">

    var pictureSource;   // picture source
    var destinationType; // sets the format of returned value 

    // Wait for Cordova to connect with the device
    //
    document.addEventListener("deviceready",onDeviceReady,false);

    // Cordova is ready to be used!
    //
    function onDeviceReady() {
        pictureSource=navigator.camera.PictureSourceType;
        destinationType=navigator.camera.DestinationType;
    }

    // Called when a photo is successfully retrieved
    //
    function onPhotoDataSuccess(imageData) {
      // Uncomment to view the base64 encoded image data
      // console.log(imageData);

      // Get image handle
      //
      var smallImage = document.getElementById('smallImage');

      // Unhide image elements
      //
      smallImage.style.display = 'block';

      // Show the captured photo
      // The inline CSS rules are used to resize the image
      //
      smallImage.src = "data:image/jpeg;base64," + imageData;
    }

    // Called when a photo is successfully retrieved
    //
    function onPhotoURISuccess(imageURI) {
      // Uncomment to view the image file URI 
      // console.log(imageURI);

      // Get image handle
      //
      var largeImage = document.getElementById('largeImage');

      // Unhide image elements
      //
      largeImage.style.display = 'block';

      // Show the captured photo
      // The inline CSS rules are used to resize the image
      //
      largeImage.src = imageURI;
    }

    // A button will call this function
    //
    function capturePhoto() {
      // Take picture using device camera and retrieve image as base64-encoded string
      navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50,
        destinationType.DATA_URL });
    }

    // A button will call this function
    //
    function capturePhotoEdit() {
      // Take picture using device camera, allow edit, and retrieve image as base64-encoded string  
      navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 20, allowEdit: true,
        destinationType.DATA_URL });
    }

    // A button will call this function
    //
    function getPhoto(source) {
      // Retrieve image file location from specified source
      navigator.camera.getPicture(onPhotoURISuccess, onFail, { quality: 50, 
        destinationType: destinationType.FILE_URI,
        sourceType: source });
    }

    // Called if something bad happens.
    // 
    function onFail(message) {
      alert('Failed because: ' + message);
    }

    </script>
  </head>
  <body>
    <button onclick="capturePhoto();">Capture Photo</button> <br>
    <button onclick="capturePhotoEdit();">Capture Editable Photo</button> <br>
    <button onclick="getPhoto(pictureSource.PHOTOLIBRARY);">From Photo Library</button><br>
    <button onclick="getPhoto(pictureSource.SAVEDPHOTOALBUM);">From Photo Album</button><br>
    <img style="display:none;width:60px;height:60px;" id="smallImage" src="" />
    <img style="display:none;" id="largeImage" src="" />
  </body>
</html>

最佳答案

capturePhoto()capturePhotoEdit() 函数都需要更新 destinationType

navigator.camera.getPicture(
    onPhotoDataSuccess,
    onFail,
    {
        quality: 50,
        destinationType.DATA_URL
    }
);

应该是这样的,

navigator.camera.getPicture(
    onPhotoDataSuccess,
    onFail,
    {
        quality: 50,
        destinationType: destinationType.DATA_URL
    }
);

关于android - 如何使用 phonegap 在 Android 手机上显示摄像头,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10173892/

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