<分区>
我想将某些 URL 中的图像动态添加到线性布局中。在运行这段代码时出现错误无法启动 Activity
ComponentInfo: android.os.NetworkOnMainThreadException at com.example.star.example.CompinfoActivity.getBitmapFromURL(CompinfoActivity.java:70) at com.example.star.example.CompinfoActivity.insertPhoto(CompinfoActivity.java:50) at com.example.star.example.CompinfoActivity.onCreate(CompinfoActivity.java:38)
请帮忙。这是我下面 Activity 的代码。
public class CompinfoActivity extends AppCompatActivity {
Dialog dialog;
LinearLayout myGallery;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_compinfo);
dialog = new Dialog(this);
dialog.requestWindowFeature(Window.FEATURE_NO_TITLE);
dialog.setContentView(R.layout.activity_compinfopopup);
dialog.getWindow().getAttributes().width = AbsListView.LayoutParams.MATCH_PARENT;
dialog.getWindow().getAttributes().height = AbsListView.LayoutParams.WRAP_CONTENT;
dialog.show();
myGallery = (LinearLayout) dialog.findViewById(R.id.mygallery);
myGallery.addView(insertPhoto("http://example.com/a.png"));
myGallery.addView(insertPhoto("http://example.com/b.png"));
myGallery.addView(insertPhoto("http://example.com/c.png"));
myGallery.addView(insertPhoto("http://example.com/d.png"));
new MyTask().execute();
}
View insertPhoto(String path){
Bitmap bm;
bm = getBitmapFromURL(path);
LinearLayout layout = new LinearLayout(getApplicationContext());
layout.setLayoutParams(new AbsListView.LayoutParams(250, 250));
layout.setGravity(Gravity.CENTER);
ImageView imageView = new ImageView(getApplicationContext());
imageView.setLayoutParams(new AbsListView.LayoutParams(220, 220));
imageView.setScaleType(ImageView.ScaleType.CENTER_CROP);
imageView.setImageBitmap(bm);
layout.addView(imageView);
return layout;
}
public static Bitmap getBitmapFromURL(String src) {
try {
URL url = new URL(src);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoInput(true);
connection.connect();
InputStream input = connection.getInputStream();
Bitmap myBitmap = BitmapFactory.decodeStream(input);
return myBitmap;
} catch (IOException e) {
e.printStackTrace();
return null;
}
}