iphone - 图像选择器弹出框

Question

AGImagePickerController *imagePickerController = [[AGImagePickerController alloc] initWithFailureBlock:^(NSError *error) {

    if (error == nil)
    {
        NSLog(@"User has cancelled.");
        [self dismissModalViewControllerAnimated:YES];
    } else
    {     
        NSLog(@"Error: %@", error);

        // Wait for the view controller to show first and hide it after that
        double delayInSeconds = 0.5;
        dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, delayInSeconds * NSEC_PER_SEC);
        dispatch_after(popTime, dispatch_get_main_queue(), ^(void){
            [self dismissModalViewControllerAnimated:YES];
        });
    }

    [[UIApplication sharedApplication] setStatusBarStyle:UIStatusBarStyleDefault animated:YES];

} andSuccessBlock:^(NSArray *info) {
    NSLog(@"Info: %@", info);
    [self dismissModalViewControllerAnimated:YES];

    [[UIApplication sharedApplication] setStatusBarStyle:UIStatusBarStyleDefault animated:YES];
}];

popover = [[UIPopoverController alloc] initWithContentViewController:imagePickerController];
[popover presentPopoverFromRect:CGRectMake(0.0, 0.0, 400.0, 400.0) 
                         inView:self.view.window
       permittedArrowDirections:UIPopoverArrowDirectionAny 
                       animated:YES];

能够显示它，但是，即使我改变它的大小它仍然是一样的，当我按下 DONE 按钮时，它删除了我的 View Controller 而不是图像选择器。请帮助。我在弹出窗口中显示它，因为我认为，这就是为什么它变慢的原因，因为图像选择器应该与 iPad 的弹出窗口一起出现。

Answer 1

您是否正在实现 AGImagePickerController 委托(delegate)？

- (void)agImagePickerController:(AGImagePickerController *)picker didFinishPickingMediaWithInfo:(NSArray *)info;

在那里你可以关闭你的UIPopoverController。