ios - 我如何提示用户打开位置服务，即转到设置→隐私→位置服务

Question

下面的代码不能再工作了，我们能做什么

[[UIApplication sharedApplication] openURL:[NSURL URLWithString: @"prefs:root=LOCATION_SERVICES"]];

以下适用于转到设置 → 您的应用程序 → 位置 但我想访问转到设置 → 隐私 → 定位服务

        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];

我遇到了和下面问题一样的问题

Open Settings app from another app programmatically in iPhone

Answer 1

如果用户不打开定位服务，我会使用此代码

 - (void)locationManager:(CLLocationManager *)manager
   didFailWithError:(NSError *)error {
     if ([[error domain] isEqualToString: kCLErrorDomain] && [error code] == kCLErrorDenied) {
       // The user denied your app access to location information.

       UIAlertView* alert=[[UIAlertView alloc] initWithTitle:@"This app does not have access to Location" message:@"You can enable access in Settings" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:@"Settings", nil];
       alert.delegate = self;
       [alert show];
     }


    NSLog(@"%@", error.description);
}

并在此代码中 UIAlertView 中处理 Settings 按钮:

- (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex
{
   NSLog(@"buttonIndex:%d",buttonIndex);

   if (buttonIndex == 1) {
       [[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];
   }
}