ios - 从查找表中解析查询对象

Question

我正在尝试编写一个 PFQuery 来获取用户的 friend 作为 User 对象。下面显示的是我的用户表和 friend 查找表。当用户创建好友时，将在好友查找表中添加一个条目。

我的想法是构建一个查询，在 Lookup 表中查询 sendingUser 或 receivingUser 等于当前用户的任何行。

NSString * const kPULLookupSendingUserKey = @"sendingUser";
NSString * const kPULLookupReceivingUserKey = @"receivingUser";
....
PULUser *acct = [PULUser currentUser];
// query where sending user is current user
PFQuery *senderQuery = [PFQuery queryWithClassName:@"FriendLookup"];
[senderQuery whereKey:kPULLookupSendingUserKey equalTo:acct];

// query where receiving user is current user
PFQuery *recQuery = [PFQuery queryWithClassName:@"FriendLookup"];
[recQuery whereKey:kPULLookupReceivingUserKey equalTo:acct];

// query that ORs the previous two together and adds a couple more constraints
PFQuery *lookupQuery = [PFQuery orQueryWithSubqueries:@[senderQuery, recQuery]];
[lookupQuery whereKey:@"isBlocked" equalTo:@NO];
[lookupQuery whereKey:@"isAccepted" equalTo:@YES];

如果我只运行 lookupQuery，它会返回当前用户是发送者或接收者的正确行。我想将该行数组作为 User 对象而不是 FriendLookup 对象。

注意 PULUser 是PFUser 的子类

// query for user where sending user key matches OID
PFQuery *userQuerySender = [PULUser query];
[userQuerySender whereKey:@"objectId" matchesKey:kPULLookupSendingUserKey inQuery:lookupQuery];

// query for user where receiving user key matches OID
PFQuery *userQueryRec = [PULUser query];
[userQueryRec whereKey:@"objectId" matchesKey:kPULLookupReceivingUserKey inQuery:lookupQuery];

// join queries together in an OR
PFQuery *query = [PFQuery orQueryWithSubqueries:@[userQuerySender, userQueryRec]];
// exclude self user from query
[query whereKey:@"objectId" notEqualTo:acct.objectId];

这将返回一个空数组。关于如何正确形成此查询的任何想法？或者是否有一种不同的方法来存储友谊可以使这项任务更容易。

Answer 1

使用include key使查询结果包含指向2个用户的指针，然后将所有用户组成一个集合并删除当前用户，然后您将拥有所有用户而无需进行二次查询。