iphone - 有 2 个图像选择器和 didFinishPickingMediaWithInfo 问题

Question

我有两个 UIImageView ，每个都应该显示来自 picker 的不同图像，但我可以使用一个委托(delegate):- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info ;

这是我的代码:

- (void) importFormLibraryForCover {


    UIImagePickerController *ipc = [[UIImagePickerController alloc]init];
    ipc.delegate = self;
    CGRect rect = CGRectMake(0 ,0, 200,660);

    pop = [[ UIPopoverController alloc]initWithContentViewController:ipc];
    [pop setDelegate:self];
    [pop presentPopoverFromRect:rect inView:self.view  permittedArrowDirections:UIPopoverArrowDirectionLeft animated:YES];
    [ipc release];


}

    - (void) importFormLibraryForAvatar {


//same above code 

}



- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info {

    [picker dismissModalViewControllerAnimated:YES];


       avatarImg.image = [info objectForKey:@"UIImagePickerControllerOriginalImage"];

// here is the problem :
         coverImg.image = [info objectForKey:@"UIImagePickerControllerOriginalImage"];



    }

问题是所有两个 imageView 都显示相同的图片，并且在 UIImagePickerController 类型的对象上找不到属性“标签”

Answer 1

您可以在 .h 文件中声明自己的枚举。

typedef enum _Type
{
    eNone,
    eCover,
    eAvatar

}EType;

同时在.h 文件中声明一个变量EType _type;。 在下面的方法中，

- (void) importFormLibraryForCover
{
  // set variable
  _type = eCover;
 ...
}

与其他方法类似，设置其他值。

在didFinishPickingMediaWithInfo中，检查_type并按要求处理。