java - 在哈希码方法中使用 ^ 的原因是什么?

标签 java hashcode xor

<分区>

我今天找到了这段代码:

private static class Node{
    private final int code1;
    private final int code2;

    public Node(int code1, int code2) {
        this.code1 = code1;
        this.code2 = code2;
    }

    @Override
    public int hashCode() {
        return (code1 * 31) ^ code2;
    }

    @Override
    public boolean equals(Object obj) {
        if (obj instanceof Node) {
            Node node = (Node) obj;
            return node.code1 == code1 && node.code2 == code2;
        }
        return false;
    }
}

哈希码使用 (code1 * 31) ^ code2; 有充分的理由吗?

根据我的理解,创建哈希码的通常方法是将当前哈希码(或第一个字段)乘以质数,然后为每个字段添加下一个字段。

为什么这里需要一个power异或运算符?

最佳答案

^ 不是幂,它是按位异或。哈希码的目的是实现随机分布,^ 的属性略优于 +,但还不足以让大多数人关心。

顺便说一句,Java 中没有幂运算符,只有 Math.pow(a, b)


我可能是错的,但我记得是这样;

您想要一个操作,每个位产生 0 或 1 的机会均等。这不包括乘法、除法、模数和、或、或移位。这留下了 ^、- 或 +。当您溢出时,您会丢失一些信息,^ 是唯一不会溢出的信息。

在上面的示例中,代码可能不够大而不会溢出,即使您改用 +,我预计差异也非常小。


我不是这方面的数学专家,但对我来说 + 似乎是更好的选择。如果您有以下内容(使用 0-255 字节,但它应该具有代表性或 int 值会发生什么)

int[] add = new int[256];
int[] xor = new int[256];

for (int i = 0; i < 256; i++)
    for (int j = 0; j < 256; j++) {
        add[(i + j) & 0xFF]++;
        xor[i ^ j]++;
    }

System.out.println("add: " + Arrays.toString(add));
System.out.println("xor: " + Arrays.toString(xor));

每个值出现的机会均等。

add: [256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256]
xor: [256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256, 256]

如果我们假设有偏分布,例如 ASCII 值的范围为 0 到 127,则有可能未在任一值中设置的位将使用 add 设置,而不是 xor。

add: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128, 127, 126, 125, 124, 123, 122, 121, 120, 119, 118, 117, 116, 115, 114, 113, 112, 111, 110, 109, 108, 107, 106, 105, 104, 103, 102, 101, 100, 99, 98, 97, 96, 95, 94, 93, 92, 91, 90, 89, 88, 87, 86, 85, 84, 83, 82, 81, 80, 79, 78, 77, 76, 75, 74, 73, 72, 71, 70, 69, 68, 67, 66, 65, 64, 63, 62, 61, 60, 59, 58, 57, 56, 55, 54, 53, 52, 51, 50, 49, 48, 47, 46, 45, 44, 43, 42, 41, 40, 39, 38, 37, 36, 35, 34, 33, 32, 31, 30, 29, 28, 27, 26, 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
xor: [128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 128, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

你取一个模数,比如 37,分布看起来更均匀(最常见和最不常见结果之间的差异较小)

添加:[243, 244, 245, 246, 247, 248, 249, 250, 251, 252, 253, 252, 251, 250, 249, 248, 247, 246, 245, 244, 243, 242, 241, 240, 239, 238, 237, 237, 237, 237, 237, 237, 238, 239, 240, 241, 242, 0, 0, ..

异或:[283, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 282, 218, 218, 218, 218, 218, 220, 220, 220, 220, 220, 220, 220, 220, 220, 220, 188, 188, 188, 188, 188, 0, 0, ...

关于java - 在哈希码方法中使用 ^ 的原因是什么?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18715052/

相关文章:

java - 在 play 框架中获取 JDBC 连接(java)

java - Eclipse IDE 显示 JPA 中复合主键类的错误

java - 调用返回结果集的方法

hadoop - 计算HDFS中的HashCode函数

java - 如何为仅包含对下一个节点的引用的节点实现HashCode()?

C、位图操作

java - Sphinx 4 中的哪个 Demo 代码更适合实时语音到文本转换?

java - hash()%n 和 n%hash() 有什么区别

algorithm - 找到一个数字与序列元素进行异或以获得给定的总和

php - XOR PHP 中的一个字符串,键是一个整数