我正在用 Java 尝试一个非常简单的 GUI。 我刚刚创建了一个带有按钮的小型 GUI,当我们单击每个按钮时,它会打开一个网站。
所以我有 3 个按钮: 按钮 1 = gmail 按钮 2 = 谷歌 button3 = 雅虎
当我点击 button1 时,它有时会打开 gmail、google 或 yahoo。 其他按钮也有同样的问题。
为什么?
这是我非常简单的代码:
import java.awt.*;
import java.awt.event.*;
import java.io.*;
import java.util.logging.Level;
import java.util.logging.Logger;
public class Gui extends Frame implements WindowListener,ActionListener {
//TextField text = new TextField(20);
Button a, b, c;
Process p1, p2, p3;
//private int numClicks = 0;
public static void main(String[] args) {
Gui myWindow = new Gui("Miquelon's");
myWindow.setSize(350,100);
myWindow.setVisible(true);
}
public Gui(String title) {
super(title);
setLayout(new FlowLayout());
addWindowListener(this);
a = new Button("Gmail");
b = new Button ("Google");
c = new Button ("Yahooooo");
add(a);
add(b);
add(c);
//add(text);
a.addActionListener(this);
b.addActionListener(this);
c.addActionListener(this);
}
public void actionPerformed(ActionEvent e)
{
try
{
{
p1 = Runtime.getRuntime().exec("cmd /c start https://mail.google.com");
p2 = Runtime.getRuntime().exec("cmd /c start https://google.com");
p3 = Runtime.getRuntime().exec("cmd /c start https://yahoo.com");
}
}
catch (IOException ex)
{
Logger.getLogger(Gui.class.getName()).log(Level.SEVERE, null, ex);
}
}
public void windowClosing(WindowEvent e) {
dispose();
System.exit(0);
}
public void windowOpened(WindowEvent e) {}
public void windowActivated(WindowEvent e) {}
public void windowIconified(WindowEvent e) {}
public void windowDeiconified(WindowEvent e) {}
public void windowDeactivated(WindowEvent e) {}
public void windowClosed(WindowEvent e) {}
}
谢谢
最佳答案
您的 actionPerformed 正在运行所有三个。您需要使用 actionPerformed 来确定按下了哪个按钮,然后运行相应的命令。
public void actionPerformed(ActionEvent e)
{
String address = "";
if(e.getSource() == a) address = "https://mail.google.com";
else if(e.getSource() == b) address = "https://google.com";
else if(e.getSource() == c) address = "https://yahoo.com";
else return; // not one of the three buttons, get out!
try
{
// only NEED to store the process if you want to do something with it later
// I just let mine dangle :) it works for me!
Runtime.getRuntime().exec("cmd /c start " + address);
}
catch (IOException ex)
{
Logger.getLogger(Gui.class.getName()).log(Level.SEVERE, null, ex);
}
}
关于java - Java中的简单GUI问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5331359/