当我运行这段代码时，它给了我IllegalArgumentException，然后执行了整个代码，但是线程 t 的名称只是默认值，而不是代码中的 Mark。
可能是什么原因？
Exception in thread "main" java.lang.IllegalArgumentException
at java.lang.Thread.setPriority(Unknown Source)
at Threads.CurrentThreadImpl.main(CurrentThreadImpl.java:11)
value of I is : 0and the thread name is : Thread-0
value of I is : 1and the thread name is : Thread-0
value of I is : 2and the thread name is : Thread-0
value of I is : 3and the thread name is : Thread-0
value of I is : 0and the thread name is : Thread-1
value of I is : 1and the thread name is : Thread-1
value of I is : 2and the thread name is : Thread-1
value of I is : 3and the thread name is : Thread-1
public class CreateThread implements Runnable{
public void run(){
for(int i = 0; i<4; i++){
System.out.println("value of I is : "+ i + "and the thread name is : "+ Thread.currentThread().getName());
}
}
}
public class CurrentThreadImpl {
public static void main(String[] args) {
CreateThread runnableObj = new CreateThread();
Thread thread = new Thread(runnableObj);
Thread t = new Thread(runnableObj);
thread.start();
t.start();
thread.setPriority(0);
t.setPriority(10);
t.setName("Mark");
}
}
最佳答案
参见 Thread#setPriority :
IllegalArgumentException - If the priority is not in the range MIN_PRIORITY to MAX_PRIORITY.
MIN_PRIORITY是 1，不是 0:
关于java - thread.setPriority(0) 给出 IllegalArgumentException，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/18944126/