java - 在循环中对奇数求和

Question

public static void main(String[] args) {

    int maxNum, sum, counter; // input value
    Scanner input = new Scanner(System.in); 

    System.out.print("How many odd numbers should I add up?: ");
    maxNum = input.nextInt();   

    sum = 0;

    for (counter = 1; counter < maxNum; counter++)
    {            
       sum = counter + maxNum;                        
    }

    System.out.println("\n" + "The sum of the odd numbers between 1 and " + maxNum + " is: " + sum);                 
}

根据那个特定的代码，它应该只通过奇数来解决加法问题。

现在我尝试了一个数字 5，根据我的输出:

How many odd numbers should I add up?: 5

The sum of the odd numbers between 1 and 5 is: 9

它有效。但是当我尝试另一个数字 10 时，出了点问题:

How many odd numbers should I add up?: 10

The sum of the odd numbers between 1 and 10 is: 19

我知道我的数学题，但是从 1 到 10 的奇数加起来不是 19，它加起来是 25。

代码有问题。任何人都可以找出问题所在吗？

Answer 1

   for (counter = 1; counter < maxNum; counter+=2)
   {
      sum += counter;                                 
   }

您添加了错误的号码。