我正在尝试存储作为抽象类的子类的对象,但这里有一个问题:
abstract class Letter {
public void store_object(Letter letter) {
HashMap<Class<? extends Letter>, ? extends Letter> map = new HashMap<>();
map.put(letter.getClass(), letter); <-- this line throws an error
}
}
class A extends Letter {}
class B extends Letter {}
map.put
抛出错误的原因是 letter
不是 Letter
的子类(它是信件
).
有没有办法将方法参数更改为 Letter 的通用子类?像这样的东西:
public void store_object(? extends Letter letter) {
或
public void store_object(Object<? extends Letter> letter) {
错误是:
no suitable method found for put(Class<CAP#1>,NewClass19.Letter)
method Map.put(Class<? extends NewClass19.Letter>,CAP#2) is not applicable
(argument mismatch; NewClass19.Letter cannot be converted to CAP#2)
method AbstractMap.put(Class<? extends NewClass19.Letter>,CAP#2) is not applicable
(argument mismatch; NewClass19.Letter cannot be converted to CAP#2)
method HashMap.put(Class<? extends NewClass19.Letter>,CAP#2) is not applicable
(argument mismatch; NewClass19.Letter cannot be converted to CAP#2)
where CAP#1,CAP#2 are fresh type-variables:
CAP#1 extends NewClass19.Letter from capture of ? extends NewClass19.Letter
CAP#2 extends NewClass19.Letter from capture of ? extends NewClass19.Letter
最佳答案
我真的不确定你想在这里做什么,但这将使你的代码编译:
abstract class Letter {
public <T extends Letter> void store_object(T letter) {
HashMap<Class<? extends Letter>, T> map = new HashMap<>();
map.put(letter.getClass(), letter); // <-- this line throws an error
}
}
class A extends Letter {}
class B extends Letter {}
为什么要生成一个新的 HashMap
每次 store_object
方法被调用?你真正的问题是什么?请阅读What is the XY problem?
相关:Canonical Java Generics FAQ
顺便说一下,Object<Anything>
总是错的,因为 Object
未参数化。
所以我看到了您的编辑,仅供引用:
private static HashMap<Class<? extends Test>, Test> map = new HashMap<>();
static void addTest(Test test) {
map.put(test.getClass(), test);
}
你的问题到底是什么?
关于java - 如何将泛型参数传递给方法?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31497514/