我正在一个类实验室工作,并且让 bwcomw 停留在我们必须编写的一种方法上:
Member[] getMembersByYear(int firstYear, int last year)
– locates and returns all members who joined between the two specified years, inclusive. This method returns the members in a Java one-dimensional array. There must be no empty slots in the array.
我对如何处理这件事感到有点困惑,我将不胜感激任何建议。这是我到目前为止所写的内容:
public class Club
{
// Define any necessary fields here ...
private ArrayList <Member> members;
/**
* Constructor for objects of class Club
*/
public Club()
{
// Initialise any fields here ...
members = new ArrayList <Member>();
}
/**
* Add a new member to the club's list of members.
* @param member The member object to be added.
*/
public void join(Member member)
{
members.add(member);
}
/**
* @return The number of members (Member objects) in
* the club.
*/
public int numberOfMembers()
{
if(members.size() > 0){
return members.size();
}
else{
return 0;
}
}
public void showMembers(){
for(Member display: members){
System.out.println(display.toString());
}
}
public void showMembersByYear(int year){
for(Member byYear: members){
if(byYear.getYear() > 0){
showMembers();
}
}
}
public Member[] getMembersByYear(int firstYear, int lastYear)
{
Member checker = new Member(); //does not work, no constructor member() exists
while((firstYear <= checker.getYear()) && (lastYear >= checker.getYear())){
}
}
public void removeMembersByYear(int year){
Iterator it = members.iterator();
}
}
最佳答案
好的。很高兴看到你试过了!首先,您可以在您的方法中创建一个ArrayList
。然后是遍历您的 members
数组,当年份落在给定范围内时,您应该将其添加到新的 ArrayList
。然后,简单地返回 ArrayList.toArray
方法。像这样的东西:
public Member[] getMembersInYear(int firstYear, int secondYear)
{
ArrayList<Member> membersInRange = new ArrayList<Member>();
for(every member in members) {
if(is in year) {
membersInRange.add(currentMember);
}
}
return membersInRange.toArray();
}
这将返回一个没有空值的数组,其中仅包含年份介于 firstYear
和 secondYear
之间的成员。
关于java - 如何返回一维数组?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16130312/