java - 如何根据条件返回 json 响应并重定向到其他 View ？

Question

我有一个搜索条件，这取决于我得到列表的结果。 如果列表仅包含 1 个数据，那么我想返回到该特定数据的编辑 View 。如果列表包含超过 1 个数据，我想返回 jsonResponse 以显示数据表。

我试过了，但是我没有得到数据表，也没有得到 View

if(reservationGridDataPage.getSize() > 1){
    GridJSONResponse jsonResponse = ReservationGridHelper.prepareResponse(reservationGridDataPage);
    jsonResponse.setiTotalDisplayRecords(gridManager.getTotalSearchedReservations(pageRequest, null, entityStateCode, searchParams));
    jsonResponse.setsEcho(sEcho);
    return jsonResponse;
}else{
    Long entityKey = null;
    List<ReservationGridData> content = reservationGridDataPage.getContent();
    for (ReservationGridData t : content) {
        entityKey = t.getId();
    }

    RedirectView redirectView = new RedirectView("/xxx/editRes?id="+entityKey);
    return new ModelAndView(redirectView);
}

Answer 1

只返回类型为String的 View 名称。然后，如果 reservationGridDataPage.getSize() > 1 返回 true，则重定向到使用 @ResponseBody 注释的 Controller 的另一个方法，它将返回您的 json 对象。

@RequestMapping(value = "//... your mapping blah blah ...", method = RequestMethod.POST)
public String method1(){
    if(reservationGridDataPage.getSize() > 1){
        return "redirect:/json-response.do";
    }else{
        Long entityKey = null;
        List<ReservationGridData> content = reservationGridDataPage.getContent();
        for (ReservationGridData t : content) {
            entityKey = t.getId();
        }

        //...
        //some other codes

        return "the-name-of-my-edit-view";
    }
}

@RequestMapping(value = "/json-response.do", method = RequestMethod.GET)
public @ResponseBody GridJSONResponse jsonResponseController(){
    //... some other codes
    GridJSONResponse jsonResponse = ReservationGridHelper.prepareResponse(reservationGridDataPage);
    jsonResponse.setiTotalDisplayRecords(gridManager.getTotalSearchedReservations(pageRequest, null, entityStateCode, searchParams));
    jsonResponse.setsEcho(sEcho);
    //...

    return GridJSONResponse;
}