假设我有一个包含请求/响应和 wsdl 文件的 xml 文件。如何通过 wsdl 验证请求/响应?
重要
我知道可以使用 Spring-Ws 或 Metro 之类的容器启用此类验证,但我希望在没有此类容器的情况下进行手动验证:
public static void main (String[] arg) {
File xmlRequest = new File(arg[0]);
File wsdlFile = new File(arg[1]);
//....
someValidator.validate(xmlRequest, wsdlFile);
}
最佳答案
如果要验证 xml,则需要为该 xml 创建 XSD。
之后就是调用验证方法,就像您所做的那样。
package com.journaldev.xml;
import java.io.File;
import java.io.IOException;
import javax.xml.XMLConstants;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;
import javax.xml.validation.Validator;
import org.xml.sax.SAXException;
public class XMLValidation {
public static void main(String[] args) {
System.out.println("EmployeeRequest.xml validates against Employee.xsd? "+validateXMLSchema("Employee.xsd", "EmployeeRequest.xml"));
System.out.println("EmployeeResponse.xml validates against Employee.xsd? "+validateXMLSchema("Employee.xsd", "EmployeeResponse.xml"));
System.out.println("employee.xml validates against Employee.xsd? "+validateXMLSchema("Employee.xsd", "employee.xml"));
}
public static boolean validateXMLSchema(String xsdPath, String xmlPath){
try {
SchemaFactory factory =
SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = factory.newSchema(new File(xsdPath));
Validator validator = schema.newValidator();
validator.validate(new StreamSource(new File(xmlPath)));
} catch (IOException | SAXException e) {
System.out.println("Exception: "+e.getMessage());
return false;
}
return true;
}
}
这里有教程:
http://www.journaldev.com/895/how-to-validate-xml-against-xsd-in-java
关于java - 如何以编程方式(!)使用 wsdl 验证 soap 请求/响应?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21461504/