我正在尝试解析谷歌搜索结果的 HTML 以获取每个结果的标题。这是通过 android 在如下所示的私有(private)嵌套类中完成的:
private class WebScraper extends AsyncTask<String, Void, String> {
public WebScraper() {}
@Override
protected String doInBackground(String... urls) {
Document doc;
try {
doc = Jsoup.connect(urls[0]).get();
} catch (IOException e) {
System.out.println("Failed to open document");
return "";
}
Elements results = doc.getElementsByClass("rc");
int count = 0;
for (Element lmnt : results) {
System.out.println(count++);
System.out.println(lmnt.text());
}
System.out.println("Count is : " + count);
String key = "test";
//noinspection Since15
SearchActivity.this.songs.put(key, SearchActivity.this.songs.getOrDefault(key, 0) + 1);
// return requested
return "";
}
}
我正在尝试解析的示例网址:http://www.google.com/#q=i+might+site:genius.com
出于某种原因,当我运行上面的代码时,我的计数打印为 0,因此结果中没有存储任何元素。任何帮助深表感谢!附言文档肯定已初始化并且 HTML 页面正在正确加载
最佳答案
此代码将在 google 中搜索“Apple”之类的词,并从结果中获取所有链接并显示它们的标题和 url。在谷歌检测到它并停止提供结果后,它可以在一天内搜索多达 500 个单词。
search="Apple"; //your word to be search on google
String userAgent = "ExampleBot 1.0 (+http://example.com/bot)";
Elements links=null;
try {
links = Jsoup.connect(google +
URLEncoder.encode(search,charset)).
userAgent(userAgent).get().select(".g>.r>a");
} catch (UnsupportedEncodingException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
for (Element link : links) {
String title = link.text();
String url = link.absUrl("href"); // Google returns URLs in
format "http://www.google.com/url?q=<url>&sa=U&ei=<someKey>".
try {
url = URLDecoder.decode(url.substring(url.indexOf('=') +
1, url.indexOf('&')), "UTF-8");
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
if (!url.startsWith("http")) {
continue; // Ads/news/etc.
}
System.out.println("Title: " + title);
System.out.println("URL: " + url);
}
关于java - Jsoup 谷歌搜索结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44121587/