我是 XML 解析的新手,我试图在 XML 之后检索数据并将其保存在 HashMap 中。我希望将每个字段中的描述、ID 和名称 保存在 HashMap 中。
<Entities TotalResults="13689">
<Entity Type="test">
<Fields>
<Field Name="description">
<Value>I want to print THIS</Value>
</Field>
<Field Name="id"><Value>1357</Value></Field>
<Field Name="vc-comments"><Value></Value></Field>
<Field Name="name">
<Value>locked manager - lock state</Value>
</Field>
<Field Name="has-linkage"><Value>N</Value></Field>
</Fields>
</Entity>
<Entity Type="test">
<Fields>
<Field Name="description"><Value>Print this</Value></Field>
<Field Name="user-06"><Value></Value></Field>
<Field Name="id"><Value>1358</Value></Field>
<Field Name="name">
<Value>locked manager - stealing a key </Value>
</Field>
<Field Name="vc-status"><Value></Value></Field>
</Fields>
</Entity>
</Entities>
最佳答案
不知道字段的时候应该使用hash map
解决你问题的常规方法是构建 pojo类 像这样
public class MyPojo
{
private Entities Entities;
public Entities getEntities ()
{
return Entities;
}
public void setEntities (Entities Entities)
{
this.Entities = Entities;
}
@Override
public String toString()
{
return "ClassPojo [Entities = "+Entities+"]";
}
}
public class Entities
{
private String TotalResults;
private Entity[] Entity;//you can use List<> insted
public String getTotalResults ()
{
return TotalResults;
}
public void setTotalResults (String TotalResults)
{
this.TotalResults = TotalResults;
}
public Entity[] getEntity ()
{
return Entity;
}
public void setEntity (Entity[] Entity)
{
this.Entity = Entity;
}
@Override
public String toString()
{
return "ClassPojo [TotalResults = "+TotalResults+", Entity = "+Entity+"]";
}
}
我做了2个pojos让你更好的理解
您可以创建与 xml 相关的其余部分。 稍后你可以使用
File file = new File("My.xml");
JAXBContext jaxbContext = JAXBContext.newInstance(MyPojo.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
MyPojo myPojo = (MyPojo) jaxbUnmarshaller.unmarshal(file);
System.out.println(myPojo);//get your value with getter setter.
//Description,id,name 可取。
In general, you use a Collection (List, Map, Set) to store objects with similar characteristics, that's why generics exist.
关于java - 如何使用 Java 从 XML 中读取值并将其保存在 Hashmap 中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47573260/