java - 查找其他单词中经常包含的小单词的实例

Question

我正在尝试编写一个文件搜索算法。在这种情况下，例如我的程序识别字符串是否在另一个单词中。例如，如果我想搜索“man”，我会得到其他实例，如“catman”或“manipulate”，这是我不想要的。

package threadedsearch;

import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.LineNumberReader;
import java.util.Scanner;

public class ThreadedSearch {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in); //antikeimeno scanner

        // parakatw pairnoume to input apo to xrhsth

        System.out.print("Target:"); 
        String Target = scanner.next();
        System.out.print("Key:");
        String key= scanner.next();

        //prospatheia anoigmatos tou arxeiou
        int appearances = 0;
        int index=0;
        //File file= new File(Target); //antikeimeno gia to arxeio

            try {

             BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(Target),"UTF-8"));
             LineNumberReader lr=new LineNumberReader(br);
             String line;

              while ((line = lr.readLine()) != null)
              {
                  index++;
                  if (line.matches(key)) {
                    System.out.println("Found at line" + index );
                  }
                  else{
                    System.out.println("To arxeio de vrethike"); //not found
                  }
              }
            } catch (FileNotFoundException e) {
                System.out.println("To arxeio de vrethike");
                e.printStackTrace();

            } catch (IOException e) {

            }



    }

Answer 1

从中汲取灵感:

public static int searchCount(File fileA, String fileWord) throws FileNotFoundException
{
    int count = 0;
    fileWord = fileWord.trim();
    Scanner scanner = new Scanner(fileA);

    while (scanner.hasNext()) // Fix issue #2
    {
        String nextWord = scanner.next().trim();
        if (nextWord.equals(fileWord)) { // Fix issue #1
            ++count; 
        }
    }
    //End While 
    return count;
}

很容易修改它以获得您要查找的内容。