我正在尝试使用 SAAJ 为这个 WSDL 调用 SOAP 网络服务。我在此处提交了对此 WSDL 的请求 http://www.webservicex.net/ws/WSDetails.aspx?WSID=64
,它生成了以下 SOAP 请求..
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<GetGeoIP xmlns="http://www.webservicex.net/">
<IPAddress>string</IPAddress>
</GetGeoIP>
</soap:Body>
</soap:Envelope>
我使用 SAAJ 生成了相同的 SOAP 请求并提交了它,但收到此错误 - 服务器无法识别 HTTP header SOAPAction 的值:。
<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><SOAP-ENV:Header/>
<SOAP-ENV:Body>
<GetGeoIP xmlns="http://www.webservicex.net/">
<IPAddress>SUNW</IPAddress>
</GetGeoIP>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
Java 代码:
package newpackage;
import javax.xml.namespace.QName;
import javax.xml.soap.*;
public class SOAPClientSAAJ {
public static void main(String args[]) throws Exception {
// Create SOAP Connection
SOAPConnectionFactory soapConnectionFactory = SOAPConnectionFactory.newInstance();
SOAPConnection soapConnection = soapConnectionFactory.createConnection();
// Send SOAP Message to SOAP Server
String url = "http://www.webservicex.net/geoipservice.asmx";
SOAPMessage soapResponse = soapConnection.call(createSOAPRequest(), url);
// print SOAP Response
System.out.print("Response SOAP Message:");
soapResponse.writeTo(System.out);
soapConnection.close();
}
private static SOAPMessage createSOAPRequest() throws Exception {
MessageFactory messageFactory = MessageFactory.newInstance();
SOAPMessage soapMessage = messageFactory.createMessage();
SOAPPart soapPart = soapMessage.getSOAPPart();
String serverURI = "http://www.w3.org/2001/XMLSchema";
// SOAP Envelope
SOAPEnvelope envelope = soapPart.getEnvelope();
envelope.addNamespaceDeclaration("xsd", serverURI);
SOAPBody body = soapMessage.getSOAPBody();
QName bodyName = new QName("http://www.webservicex.net/", "GetGeoIP" );
SOAPBodyElement bodyElement = body.addBodyElement(bodyName);
QName name = new QName("IPAddress");
SOAPElement symbol = bodyElement.addChildElement(name);
symbol.addTextNode("SUNW");
soapMessage.saveChanges();
/* Print the request message */
System.out.print("Request SOAP Message:");
soapMessage.writeTo(System.out);
System.out.println();
return soapMessage;
}
}
最佳答案
添加
MimeHeaders headers = soapMessage.getMimeHeaders();
headers.addHeader("SOAPAction", "http://www.webservicex.net/" + "GetGeoIP");
关于java - 服务器无法识别 HTTP header SOAPAction : 的值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26248323/