java - 显示偶数后跟所有奇数

Question

下面写的代码是正确的，但我想缩短这段代码。

Write a program in java to enter 10 numbers in Single dimensional array and arrange them in such a way that all even numbers are followed by all odd numbers.

int a[] = new int[6];
int b[] = new int[6];
int i, j;
int k = 0;
System.out.println("enter array");
for (i = 0; i < 6; i++) {  
    a[i] = sc.nextInt();
}
for (j = 0; j < 6; j++) {
    if (a[j] % 2 == 0) {
        b[k] = a[j];
        k++;
    }
}
for (j = 0; j < 6; j++) {
    if (a[j] % 2 != 0) {
        b[k] = a[j];
        k++;
    }
}
System.out.println("out-put");
for (i = 0; i < 6; i++) {  
    System.out.println(b[i]);
}

我可以在单个 for 循环而不是两个 for 循环中安排偶数和奇数吗？我正在使用两个 for 循环将偶数和奇数传输到 b[] 数组中。请缩短代码。一个 for 循环遍历用于检查偶数，第二个用于检查奇数。

Answer 1

这是一个简单的程序。

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
import java.util.Scanner;

/**
 *
 * @author Momir Sarac
 */
public class GroupByEvenAndOddNumbers {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        // create a collection
        List<Integer> listOfNumbers = new ArrayList<>();
        // do code within a loop for 10 times
        for(int i=0;i<10;i++)
        {
            //print to screen this text
            System.out.println("Input your number:");
            //get next input integer
            int number = scanner.nextInt();
            // add it to collection
            listOfNumbers.add(number);
        }
        // sort this collection, list of numbers
        // convert all numbers(positive and negative ) within to 0 or 1 depending whether or not they are even or odd and sort them accordignaly.
        Collections.sort(listOfNumbers, Comparator.comparingInt(n -> Math.floorMod(n, 2)));
        //print sorted collection
        System.out.println("Ordered list ..." + listOfNumbers);
    }
}