java - 如何在 Mule Studio 中为 Java 组件提供属性 Bean？

Question

在 Mule Studio 3.5 中，直接在 XML 和流中，我有以下声明:

<component class="fr.esb.bo.GenerateReportFileComponent" doc:name="BOreport">           
            <spring:property name="boServices" ref="boServices"/>
</component>

当我用这个启动 Mule 时，出现以下错误

org.xml.sax.SAXParseException: cvc-complex-type.2.4.a: Invalid content was found starting with element 'spring:property'. One of '{"http://www.mulesoft.org/schema/mule/core":annotations, "http://www.mulesoft.org/schema/mule/core":abstract-interceptor, "http://www.mulesoft.org/schema/mule/core":interceptor-stack, "http://www.mulesoft.org/schema/mule/core":abstract-entry-point-resolver-set, "http://www.mulesoft.org/schema/mule/core":abstract-entry-point-resolver, "http://www.mulesoft.org/schema/mule/core":abstract-object-factory, "http://www.mulesoft.org/schema/mule/core":abstract-lifecycle-adapter-factory, "http://www.mulesoft.org/schema/mule/core":binding}' is expected.

我明白了，但是我怎样才能将我的 boServices bean 提供给我的组件呢？ 使用自定义转换器，效果很好。

Answer 1

将您的类定义为 Spring bean:

<spring:beans>
  <spring:bean id="restaurantWaiter" scope="prototype" class="com.foo.RestaurantWaiter">
    <spring:property name="kitchenService">
        <spring:ref local="kitchenService"/>
    </spring:property>
  </spring:bean>
</spring:beans>

<component>
  <spring-object bean="restaurantWaiter"/>
</component>

解释为 here .