我正在制作一个小型纸牌游戏。在此游戏中,新玩家是扩展一般玩家类的 AIPlayer 或 HumanPlayer 类的实例。
目前要生成播放器,我有以下代码:
private List<Player> players;
HumanPlayer playerA = new HumanPlayer("playerA");
playerA.addObserver(gameModelObserver);
players.add(playerA);
AIPlayer playerB = new AIPlayer("playerB");
playerB.addObserver(gameModelObserver);
players.add(playerB);
AIPlayer playerC = new AIPlayer("playerC");
playerC.addObserver(gameModelObserver);
players.add(playerC);
HumanPlayer playerD = new HumanPlayer("playerD");
playerD.addObserver(gameModelObserver);
players.add(playerD);
是否可以动态生成这些类? 我可以做一些事情,比如用玩家名称和 boolean 值迭代链表的所有元素,以指示它们是 AI 还是人类,然后为它们生成一个类的实例。如果是,怎么办?
编辑:为了更清楚,我正在寻找这样的事情是否可行:
for(int i=0; i<x; i++){
player i = new Player("i");
i.addObserver(gameModelObserver);
players.add(i); }
最佳答案
这不能回答您的问题,但是,也许可以解决您的问题:
private List<Player> players;
public void createPlayerByName(String name, Class type) {
Player player = type.equals(HumanPlayer) ? new HumanPlayer(name) : new IAPlayer(name);
player.addObserver(gameModelObserver);
players.add(player);
}
public void createHumanPlayerByName(String name) {
createPlayerByName(name, HumanPlayer.class);
}
public void createIAPlayerByName(String name) {
createPlayerByName(name, AIPlayer.class);
}
因此对于您的列表,您只需要这样做:
for (String name : humanNameList) {
createHumanPlayerByName(name);
}
for (String name : aiNameList) {
createAIPlayerByName(name);
}
关于Java 即时创建类的实例,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31476208/