在此作业中,您将使用一个小程序来显示扑克牌的图像。该小程序应从您下载的“图像”文件夹中加载一副 52 张纸牌图像。该小程序应洗牌(使用随机数生成器)并显示洗牌后的前 10 张牌。将卡片分成两排,每排五张。
我的小程序部分工作,但当我运行小程序查看器时,显示的是同一张卡片十次。这是我的代码:
package CTY;
import java.applet.Applet;
import java.awt.Graphics;
import java.awt.Image;
import java.util.Random;
public class Exercise12 extends Applet {
Image c1;
Image c2;
Image c3;
Image c4;
Image c5;
Image c6;
Image c7;
Image c8;
Image c9;
Image c10;
public void init() {
Random random = new Random();
String cards[][] = {
{ "cards/c1.gif", "cards/c2.gif", "cards/c3.gif", "cards/c4.gif", "cards/c5.gif", "cards/c6.gif",
"cards/c7.gif", "cards/c8.gif", "cards/c9.gif", "cards/c10.gif", "cards/cj.gif",
"cards/ck.gif", "cards/cq.gif" },
{ "cards/s1.gif", "cards/s2.gif", "cards/s3.gif", "cards/s4.gif", "cards/s5.gif", "cards/s6.gif",
"cards/s7.gif", "cards/s8.gif", "cards/s9.gif", "cards/s10.gif", "cards/sj.gif",
"cards/sk.gif", "cards/sq.gif" },
{ "cards/d1.gif", "cards/d2.gif", "cards/d3.gif", "cards/d4.gif", "cards/d5.gif", "cards/d6.gif",
"cards/d7.gif", "cards/d8.gif", "cards/d9.gif", "cards/d10.gif", "cards/dj.gif",
"cards/dk.gif", "cards/dq.gif" },
{ "cards/h1.gif", "cards/h2.gif", "cards/h3.gif", "cards/h4.gif", "cards/h5.gif", "cards/h6.gif",
"cards/h7.gif", "cards/h8.gif", "cards/h9.gif", "cards/h10.gif", "cards/hj.gif",
"cards/hk.gif", "cards/hq.gif" } };
int Card[] = new int[10];
int Suit[] = new int[10];
int suit = random.nextInt(4);
int card = random.nextInt(10);
boolean newCard = false;
for (int i = 0; i < 10; i++) {
while (newCard == false) {
newCard = true;
suit = random.nextInt(4);
card = random.nextInt(13);
for (int j = 0; j < i; j++) {
if (Card[j] == card && Suit[j] == suit ) {
newCard = false;
}
}
}
Card[i] = card;
Suit[i] = suit;
}
c1 = getImage(getDocumentBase(),
cards[Suit[0]][Card[0]]);
c2 = getImage(getDocumentBase(),
cards[Suit[1]][Card[1]]);
c3 = getImage(getDocumentBase(),
cards[Suit[2]][Card[2]]);
c4 = getImage(getDocumentBase(),
cards[Suit[3]][Card[3]]);
c5 = getImage(getDocumentBase(),
cards[Suit[4]][Card[4]]);
c6 = getImage(getDocumentBase(),
cards[Suit[5]][Card[5]]);
c7 = getImage(getDocumentBase(),
cards[Suit[6]][Card[6]]);
c8 = getImage(getDocumentBase(),
cards[Suit[7]][Card[7]]);
c9 = getImage(getDocumentBase(),
cards[Suit[8]][Card[8]]);
c10 = getImage(getDocumentBase(),
cards[Suit[9]][Card[9]]);
}
public void paint(Graphics graphics) {
graphics.drawImage(c1, 30, 30, this);
graphics.drawImage(c2, 30, 150, this);
graphics.drawImage(c3, 120, 30, this);
graphics.drawImage(c4, 120, 150, this);
graphics.drawImage(c5, 210, 30, this);
graphics.drawImage(c6, 210, 150, this);
graphics.drawImage(c7, 300, 30, this);
graphics.drawImage(c8, 300, 150, this);
graphics.drawImage(c9, 390, 30, this);
graphics.drawImage(c10, 390, 150, this);
}
}
最佳答案
循环问题,因为 newCard 标志将在一次迭代后始终为真
for (int i = 1; i <=10; i++) {
while (newCard == false) {
newCard = true;
suit = random.nextInt(4);
card = random.nextInt(13);
for (int j = 0; j < i; j++) {
if (Card[j] == card && Suit[j] == suit ) {
newCard = false;
}
}
}
Card[i] = card;
Suit[i] = suit;
}
关于java - 洗牌和显示 10 java 小程序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31689840/