java - 如何找到数组中元素的索引？

Question

我正在尝试解决 this问题:

String[] names = {
"Elena", "Thomas", "Hamilton", "Suzie", "Phil", "Matt", "Alex",
"Emma", "John", "James", "Jane", "Emily", "Daniel", "Neda",
"Aaron", "Kate"
};

int[] times = {
341, 273, 278, 329, 445, 402, 388, 275, 243, 334, 412, 393, 299,
343, 317, 265
};

基本上有2个数组，一个是名字，一个是时间，数组索引是匹配的(例如Elena的时间是341)，我要找到跑得最快的人，所以谁的时间最小就是最快的。

首先我找到了 times 数组中的最小值。

for (int i = 0; i < array.length; i++) {
    if(times[i] < fastest)
        fastest = times[i];
}

但我不知道如何匹配名称数组和时间数组，我试过了但是没有用

System.out.println(Arrays.asList(names).indexOf(fastest));

Answer 1

怎么样:

public class test {


public static void main(String[] args)
{

    String[] names = {
            "Elena", "Thomas", "Hamilton", "Suzie", "Phil", "Matt", "Alex",
            "Emma", "John", "James", "Jane", "Emily", "Daniel", "Neda",
            "Aaron", "Kate"
            };

            int[] times = {
            341, 273, 278, 329, 445, 402, 388, 275, 243, 334, 412, 393, 299,
            343, 317, 265
            };

            int fastest = Integer.MAX_VALUE;
    int slowestRunnner = 0;

            for (int i = 0; i < times.length; i++) {
                if(times[i] < fastest)
                {
                    fastest = times[i];
                    slowestRunnner = i;
                }
            }

            System.out.println(names[slowestRunnner]);
}
}

System.out.println(names[slowestRunner]);