java - 失败的许可访问 XACML

Question

我目前正在尝试为一个应用程序实现 XACML，并且刚刚开始使用 AuthZForce 库来解决它。我有一个示例策略，例如:

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<Policy xmlns="urn:oasis:names:tc:xacml:3.0:core:schema:wd-17" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" PolicyId="urn:oasis:names:tc:xacml:2.0:conformance-test:IIA1:policy" RuleCombiningAlgId="urn:oasis:names:tc:xacml:3.0:rule-combining-algorithm:deny-overrides" Version="1.0">
    <Description>
        Policy for Conformance Test IIA001.
    </Description>
    <Target/>
    <Rule Effect="Permit" RuleId="urn:oasis:names:tc:xacml:2.0:conformance-test:IIA1:rule">
        <Description>
            Julius Hibbert can read or write Bart Simpson's medical record.
        </Description>
        <Target>
            <AnyOf>
                <AllOf>
                    <Match MatchId="urn:oasis:names:tc:xacml:1.0:function:string-equal">
                        <AttributeValue DataType="http://www.w3.org/2001/XMLSchema#string">Julius Hibbert</AttributeValue>
                        <AttributeDesignator AttributeId="urn:oasis:names:tc:xacml:1.0:subject:subject-id" Category="urn:oasis:names:tc:xacml:1.0:subject-category:access-subject" DataType="http://www.w3.org/2001/XMLSchema#string" MustBePresent="false"/>
                    </Match>
                </AllOf>
            </AnyOf>
            <AnyOf>
                <AllOf>
                    <Match MatchId="urn:oasis:names:tc:xacml:1.0:function:anyURI-equal">
                        <AttributeValue DataType="http://www.w3.org/2001/XMLSchema#anyURI">http://medico.com/record/patient/BartSimpson</AttributeValue>
                        <AttributeDesignator AttributeId="urn:oasis:names:tc:xacml:1.0:resource:resource-id" Category="urn:oasis:names:tc:xacml:3.0:attribute-category:resource" DataType="http://www.w3.org/2001/XMLSchema#anyURI" MustBePresent="false"/>
                    </Match>
                </AllOf>
            </AnyOf>
            <AnyOf>
                <AllOf>
                    <Match MatchId="urn:oasis:names:tc:xacml:1.0:function:string-equal">
                        <AttributeValue DataType="http://www.w3.org/2001/XMLSchema#string">read</AttributeValue>
                        <AttributeDesignator AttributeId="urn:oasis:names:tc:xacml:1.0:action:action-id" Category="urn:oasis:names:tc:xacml:3.0:attribute-category:action" DataType="http://www.w3.org/2001/XMLSchema#string" MustBePresent="false"/>
                    </Match>
                </AllOf>
                <AllOf>
                    <Match MatchId="urn:oasis:names:tc:xacml:1.0:function:string-equal">
                        <AttributeValue DataType="http://www.w3.org/2001/XMLSchema#string">write</AttributeValue>
                        <AttributeDesignator AttributeId="urn:oasis:names:tc:xacml:1.0:action:action-id" Category="urn:oasis:names:tc:xacml:3.0:attribute-category:action" DataType="http://www.w3.org/2001/XMLSchema#string" MustBePresent="false"/>
                    </Match>
                </AllOf>
            </AnyOf>
        </Target>
    </Rule>
</Policy>

所以我尝试根据这个策略创建XACML请求，希望它能被PDP允许，代码如下:

System.setProperty("javax.xml.accessExternalSchema", "http");

        File a = new File("pdp.xml");


        final PdpEngineConfiguration pdpEngineConf = PdpEngineConfiguration.getInstance(a.toURI().toString()); 
        final BasePdpEngine pdp = new BasePdpEngine(pdpEngineConf);
        final DecisionRequestBuilder<?> requestBuilder = pdp.newRequestBuilder(-1, -1);
        String issuer="Julius Hibbert";

        final AttributeFqn subjectIdAttributeId = AttributeFqns.newInstance(XACML_1_0_ACCESS_SUBJECT.value(), Optional.ofNullable(issuer), XacmlAttributeId.XACML_1_0_SUBJECT_ID.value());
        final AttributeBag<?> subjectIdAttributeValues = Bags.singletonAttributeBag(StandardDatatypes.STRING, new StringValue("Julius Hibbert"));
        requestBuilder.putNamedAttributeIfAbsent(subjectIdAttributeId, subjectIdAttributeValues);

        final AttributeFqn resourceIdAttributeId = AttributeFqns.newInstance(XACML_3_0_RESOURCE.value(), Optional.ofNullable(issuer), XacmlAttributeId.XACML_1_0_RESOURCE_ID.value());
        final AttributeBag<?> resourceIdAttributeValues = Bags.singletonAttributeBag(StandardDatatypes.STRING, new StringValue("http://medico.com/record/patient/BartSimpson"));
        requestBuilder.putNamedAttributeIfAbsent(resourceIdAttributeId, resourceIdAttributeValues);

        // Add action ID attribute (action category), no issuer, string value "GET"
        final AttributeFqn actionIdAttributeId = AttributeFqns.newInstance(XACML_3_0_ACTION.value(), Optional.ofNullable(issuer), XacmlAttributeId.XACML_1_0_ACTION_ID.value());
        final AttributeBag<?> actionIdAttributeValues = Bags.singletonAttributeBag(StandardDatatypes.STRING, new StringValue("write"));
        requestBuilder.putNamedAttributeIfAbsent(actionIdAttributeId, actionIdAttributeValues);

        // No more attribute, let's finalize the request creation
        final DecisionRequest request = requestBuilder.build(false);
        // Evaluate the request
        final DecisionResult result = pdp.evaluate(request);
        if(result.getDecision() == DecisionType.PERMIT) {
            // This is a Permit :-)
            System.out.println("ok");
        } else {
            // Not a Permit :-( (maybe Deny, NotApplicable or Indeterminate)
            System.out.println("not ok");
        }

但是当我运行代码时，它给出了 NotApplicable 的结果，但我不确定为什么。我的代码有什么错误吗？

Answer 1

resource-id 属性的数据类型在您的代码中是错误的。您将其设置为 string，而在策略中匹配需要 anyURI。所以只需更改这行代码:

final AttributeBag<?> resourceIdAttributeValues = Bags.singletonAttributeBag(StandardDatatypes.STRING, new StringValue("http://medico.com/record/patient/BartSimpson"));

到

final AttributeBag<?> resourceIdAttributeValues = Bags.singletonAttributeBag(StandardDatatypes.ANYURI, new AnyUriValue("http://medico.com/record/patient/BartSimpson"));

此外，您将属性的 Issuer 设置为 Julius Hibbert 有什么特别的原因吗？否则将其设置为 null，不用担心。

String issuer = null;