我正在创建一个 TicTacToe 游戏,但我遇到了字符串问题
代码:
import java.util.Scanner;
public class TicTacToe {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String player1Letter;
String player2Letter;
System.out.print("Player 1 Name: ");
String player1 = input.next();
System.out.print('\f');
System.out.print("Player 2 Name: ");
String player2 = input.next();
System.out.print('\f');
System.out.print(player1 + ", Choose X or O: ");
String letter = input.next();
if (letter.equalsIgnoreCase("x")) {
player1Letter = "X";
} else {
player2Letter = "O";
}
if (letter.equalsIgnoreCase("o")) {
player1Letter = "O";
} else {
player2Letter = "X";
}
System.out.print('\f');
System.out.println("How To");
System.out.println("-------");
System.out.println();
System.out.println(" 1 | 2 | 3 ");
System.out.println("-----------");
System.out.println(" 4 | 5 | 6 ");
System.out.println("-----------");
System.out.println(" 7 | 8 | 9 ");
System.out.println();
while (true) {
System.out.print("Type 'begin' To Begin: ");
String begin = input.next();
if (begin.equalsIgnoreCase("begin")) {
break;
} else if (!begin.equals("begin")) {
System.out.print('\f');
System.out.println("Incorrect Syntax");
System.out.println();
}
}
System.out.println(player1 + "'s Turn " + player1Letter);
System.out.println("-----------------------------------");
System.out.println();
System.out.println(" | | ");
System.out.println("-----------");
System.out.println(" | | ");
System.out.println("-----------");
System.out.println(" | | ");
}
}
在它说的底部
System.out.println(player1 + "'s Turn " + player1Letter);
我收到错误提示“变量 player1Letter 可能尚未初始化”。我在 if 语句外创建了字符串,并在 if 语句内初始化了它们。现在我调用它,我不知道这里出了什么问题。谢谢!
最佳答案
像这样更改您的初始化代码:
if (letter.equalsIgnoreCase("x")) {
player1Letter = "X";
player2Letter = "O";
} else {
player1Letter = "O";
player2Letter = "X";
}
所以你总是会初始化这两个变量
关于java - 字符串初始化,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33511270/