java - 不要在 JAVA 中从字符串的开头/结尾修剪制表符 (\t)

Question

我有一个输入流，其中包含由制表符 (\t) 分隔的字段 看起来像这样

String str = "  acc123\tdpId123\t2011-01-01\t2022-01-01\thello@xyz.com\tIN\t1233\tSOMETHING      ";

当我执行 str = str.trim(); 和

时效果很好

strArray = str.split("\t", -1); 
strArray=["acc123","dpId123","2011-01-01","2022-01-01","hello@xyz.com","IN","1233","SOMETHING"] will give size as 8 

但输入记录中的最后一个字段不是必填项，可以跳过。

所以输入也可以像这样。

 String str1 = "acc123\tdpId123\t2011-01-01\t2022-01-01\thello@xyz.com\tIN\t1233\t";

但在这种情况下，最后一个字段应该为空，但是当我在修剪和拆分后使用此字符串时，我的大小为 7

str1 = str1.trim();      
strArray = str1.split("\t", -1); 
      strArray=["acc123","dpId123","2011-01-01","2022-01-01","hello@xyz.com","IN","1233"]will give size as 7

但是我想要

strArray=["acc123","dpId123","2011-01-01","2022-01-01","hello@xyz.com","IN","1233",""]

如何避免这种情况？

Answer 1

你去吧:

String str1 = "   acc123\tdpId 123\t201 1-01-01\t2022-01-01\thello@xyz.com\tIN\t1233\t";
str1 = str1.replaceAll("^[ ]+", ""); // removing leading spaces
str1 = str1.replaceAll("[ ]+$", ""); // removing trailing spaces
String[] split = str1.split("\t", -1);

System.out.println(Arrays.toString(split));
System.out.println(split.length);

String#trim方法还会删除 \t。为了处理这个问题，我使用正则表达式仅删除了前导和尾随空格。

输出:

[acc123, dpId 123, 201 1-01-01, 2022-01-01, hello@xyz.com, IN, 1233, ]
8