是否可以延长 servlet 3.0 异步 servlet 的超时时间。 我尝试在超时方法中执行此操作，但仍然完成了异步请求。
延长超时的最佳方法是什么，这样异步 servlet 永远不会完成
发送
最佳答案
Just change the asyncCtx.setTimeout(12000) in code.
Please find a simple implementation
它会进入一个无限循环，永远不会跳出它
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.AsyncContext;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet(urlPatterns = "/AsyncLongRunningServlet", asyncSupported = true)
public class AsyncLongRunningServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
protected void doGet(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
System.out.println("Request Processing Thread "+Thread.currentThread().getName());
request.setAttribute("org.apache.catalina.ASYNC_SUPPORTED", true);
response.setContentType("text/html");
PrintWriter printWriter=response.getWriter();
printWriter.println("<html><head><title>Asynchronous servlet</title></head><body>");
printWriter.println("Request Processing Thread "+Thread.currentThread().getName());
printWriter.println("<br>");
printWriter.println("<progress id='progress' max='100')></progress>");
printWriter.println("<br>");
AsyncContext asyncCtx = request.startAsync();
asyncCtx.addListener(new AppAsyncListener());
asyncCtx.setTimeout(12000);
//release of request processing thread
asyncCtx.start(() ->{
printWriter.println("<br>");
printWriter.println("Async thread Name "+Thread.currentThread().getName());
printWriter.println("<br>");
int i=0;
while(i<100)
{
printWriter.println("<script>document.getElementById('progress').value=\""+i+"\";</script>");
printWriter.flush();
try {
Thread.sleep(100);
} catch (Exception e) {
}
}
printWriter.println("</body></html>");
asyncCtx.complete();
}
);
printWriter.println("<br>");
printWriter.println("End of response");
}
}
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.AsyncEvent;
import javax.servlet.AsyncListener;
import javax.servlet.ServletResponse;
import javax.servlet.annotation.WebListener;
@WebListener
public class AppAsyncListener implements AsyncListener {
@Override
public void onComplete(AsyncEvent asyncEvent) throws IOException {
System.out.println("AppAsyncListener onComplete");
// we can do resource cleanup activity here
}
@Override
public void onError(AsyncEvent asyncEvent) throws IOException {
System.out.println("AppAsyncListener onError");
//we can return error response to client
}
@Override
public void onStartAsync(AsyncEvent asyncEvent) throws IOException {
System.out.println("AppAsyncListener onStartAsync");
//we can log the event here
}
@Override
public void onTimeout(AsyncEvent asyncEvent) throws IOException {
System.out.println("AppAsyncListener onTimeout");
//we can send appropriate response to client
ServletResponse response = asyncEvent.getAsyncContext().getResponse();
PrintWriter out = response.getWriter();
out.write("TimeOut Error in Processing");
}
}
关于java - Servlet 3.0 异步超时，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/4796410/