java - 如何使用 smack Java 获取 IQ 标签？

Question

实际上，问题是当我的 xmpp 客户端发送 friend 邀请，然后接收者批准了邀请，openfire 服务器再次向发起者/邀请发送者推送一个订阅数据包被授权，这就是我要防止的原因这是通过使用 IQ 标签自动过滤它然后自动授权它。

但是使用 PacketListener，我无法获取 IQ 标签...

我该怎么做？

@Override
public void processPacket(Packet packet) {
    Log.i(TAG, "SECOND subscription");
    Log.d(TAG, "SECOND: "+packet.toXML());
    if (packet instanceof Presence) {
        Presence p = (Presence) packet;
        Log.d(TAG, "TYPE-Presence: "+p.getType());
        if (p.getType() != Presence.Type.subscribe)
        return;
        String from = p.getFrom();
        Log.d(TAG, "PACKET from: "+from);
        Notification notification = new Notification(android.R.drawable.stat_notify_more, mService.getString(
                R.string.AcceptContactRequest, from), System.currentTimeMillis());
        notification.flags = Notification.FLAG_AUTO_CANCEL;
        Intent intent = new Intent(mService, Subscription.class);
        intent.setData(Contact.makeXmppUri(from));
        notification.setLatestEventInfo(mService, from, mService
                .getString(R.string.AcceptContactRequestFrom, from), PendingIntent.getActivity(mService, 0,
                        intent, PendingIntent.FLAG_ONE_SHOT));
        int id = p.hashCode();
        mService.sendNotification(id, notification);
    }
}

Answer 1

可以使用“IQTypeFilter”过滤器过滤掉传入的 IQ。这是说明该方法的示例代码。

    connection.connect();

    /* packet listener: listen for incoming messages of type IQ on the connection (whatever the buddy) */
    PacketFilter filter = new IQTypeFilter(IQ.Type.SET); // or IQ.Type.GET etc. according to what you like to filter. 

    connection.addPacketListener(new PacketListener() { 
        public void processPacket(Packet packet) {
            // HERE YOU PUT YOUR CODE TO HANDLE THE IQ MESSAGE
        }
    }, filter);