java - 正则表达式测试字符串是否包含数字

Question

我想测试一个字符串是否包含数字(至少一个数字) 所以我尝试了这个:

public class Test {
private static final String DIGIT_PATTERN = "^(?=.*\\d)";
private static final Pattern DIGIT_PATTERN_COMPILED = Pattern.compile(DIGIT_PATTERN);

/**
 * 
 * @param args
 */
public static void main(String[] args) {
    String passwordOne = "123";
    String passwordTwo = "abc";

    Matcher matcher = null;

    matcher = DIGIT_PATTERN_COMPILED.matcher(passwordOne);

    if(!matcher.matches()) {
        System.out.println("Password " + passwordOne + " contains no number");
    } else {
        System.out.println("Password " + passwordOne + " contains number");
    }

    matcher = DIGIT_PATTERN_COMPILED.matcher(passwordTwo);

    if(!matcher.matches()) {
        System.out.println("Password " + passwordTwo + " contains no number");
    } else {
        System.out.println("Password " + passwordTwo + " contains number");
    }   
}
}

不幸的是，两个 if 子句都打印出它不包含数字。 我是不是用错了正则表达式？

Answer 1

最基本的模式

".*[0-9].*"

用你的代码为我工作。