Java 在自定义位置拆分字符串

Question

我有大字符串，例如:

String = "ABC114.553111.325785.658EFG114.256114.589115.898";

我想实现:

String1 = "ABC";
String2 = "114.553";
String3 = "111.325";
String4 = "785.658";

有时不是三位数字然后是点，然后是四位数字。但总是在数字之前有三个字母。

Answer 1

您可以使用以下正则表达式:

([^\.]){3}(\....)?

这里有一个程序...

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class C {

    public static void main(String[] args) {
        String a = "([^\\.]){3}(\\....)?";
        String b = "ABC114.553111.325785.658EFG114.256114.589115.898";

        Pattern pattern = Pattern.compile(a);
        Matcher matcher = pattern.matcher(b);

        while (matcher.find()) {
            System.out.println("found: " + matcher.group(0));
        }
    }
}

输出

found: ABC
found: 114.553
found: 111.325
found: 785.658
found: EFG
found: 114.256
found: 114.589
found: 115.898