我想要一种使用我的用户名或电子邮件登录我的 Parse 帐户的方法。 我现在拥有的代码仅适用于我的用户名。我想知道一种方法来识别文本字段是否有用户名或电子邮件。
这是代码，
private class SignInOnClickListener implements View.OnClickListener {
@Override
public void onClick(View v) {
// Get the username and password from the view
final String username_email = mUsernameEmailEtxt.getText().toString().toLowerCase();
final String password = mPasswordEtxt.getText().toString();
if (isFormInputValid(username_email, password)) {
if (android.util.Patterns.EMAIL_ADDRESS.matcher(username_email).matches()) { // HERE!
final String email = mUsernameEmailEtxt.getText().toString();
ParseUser.logInInBackground(email, password, new LogInCallback() {
public void done(ParseUser user, ParseException e) {
if (user != null) {
// Hooray! The user is logged in.
Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
startActivity(intent);
finish();
}
}
});
} else {
ParseUser.logInInBackground(username_email, password, new LogInCallback() {
public void done(ParseUser user, ParseException e) {
if (user != null) {
// Hooray! The user is logged in.
Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
startActivity(intent);
finish();
} else {
findViewById(R.id.error).setVisibility(View.VISIBLE);
}
}
});
}
}
}
}
private class SignInOnClickListener implements View.OnClickListener {
@Override
public void onClick(View v) {
// Get the username and password from the view
final String username_email = mUsernameEmailEtxt.getText().toString().toLowerCase();
final String password = mPasswordEtxt.getText().toString();
if (isFormInputValid(username_email, password)) {
if (android.util.Patterns.EMAIL_ADDRESS.matcher(username_email).matches()) { // HERE!
final String email = mUsernameEmailEtxt.getText().toString();
ParseUser.logInInBackground(email, password, new LogInCallback() {
public void done(ParseUser user, ParseException e) {
if (user != null) {
// Hooray! The user is logged in.
Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
startActivity(intent);
finish();
}
}
});
} else {
ParseUser.logInInBackground(username_email, password, new LogInCallback() {
public void done(ParseUser user, ParseException e) {
if (user != null) {
// Hooray! The user is logged in.
Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
startActivity(intent);
finish();
} else {
findViewById(R.id.error).setVisibility(View.VISIBLE);
}
}
});
}
}
}
}
更新:我已发布日志并进行了一些更改(来源:@kevin)，检测到电子邮件但拒绝登录。
这是代码，
private class SignInOnClickListener implements View.OnClickListener {
@Override
public void onClick(View v) {
// Get the username and password from the view
final String username_email = mUsernameEmailEtxt.getText().toString().toLowerCase();
final String password = mPasswordEtxt.getText().toString();
final String email = mUsernameEmailEtxt.getText().toString().toLowerCase();
if (isFormInputValid(username_email, password)) {
if (username_email.indexOf('@') != -1) { // HERE!
Log.d("detector", "username_email detected as email:" + email.toString());
ParseUser.logInInBackground(email, password, new LogInCallback() {
public void done(ParseUser user, ParseException e) {
if (user != null) {
// Hooray! The user is logged in.
Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
startActivity(intent);
finish();
}
}
});
} else {
Log.d("detector", "username_email detected as username:" + username_email.toString());
ParseUser.logInInBackground(username_email, password, new LogInCallback() {
public void done(ParseUser user, ParseException e) {
if (user != null) {
// Hooray! The user is logged in.
Intent intent = new Intent(getBaseContext(), MainActivity.class).addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_CLEAR_TASK);
startActivity(intent);
finish();
} else {
findViewById(R.id.error).setVisibility(View.VISIBLE);
Log.d("error", "username or email invalid");
}
}
});
}
}
}
}
最佳答案
这并不难，您应该使用 Android 中已经提供的内置模式来完美地检查电子邮件 ID。
public final static boolean isEmailIDValid(CharSequence email) {
if (email == null)
return false;
return android.util.Patterns.EMAIL_ADDRESS.matcher(email).matches();
}
不那么复杂，并且可以在 API 8 以上的所有 Android 版本上完美运行。我一直在支持 API 14 及更高版本的任何应用程序中使用它，从来没有遇到任何问题。
关于java - 从 edittext Android 识别电子邮件，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/31981496/