我有一串单词如下:
String words = "disaster kill people action scary seriously world murder loose world";
现在,我希望将每 2 个单词拆分并将它们存储到一个列表中,这样它会产生如下内容:
[disaster kill, people action, scary seriously,...]
我的代码的问题是它会在遇到空格时拆分。我该如何修改它,以便它仅在遇到每 2 个空格时才会被添加到列表中,并保留每个单词后的空格)
我的代码:
ArrayList<String> wordArrayList = new ArrayList<String>();
for(String word : joined.split(" ")) {
wordArrayList.add(word);
}
谢谢。
最佳答案
使用这个正则表达式:(?<!\\G\\S+)\\s
.
证明:
String words = "disaster kill people action scary seriously world murder loose world";
String[] result = words.split("(?<!\\G\\S+)\\s");
System.out.printf("%s%n", Arrays.toString(result));
结果:
[disaster kill, people action, scary seriously, world murder, loose world]
关于java - 每 2 个单词后拆分字符串并存储到列表中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37349455/