java - 为什么 JPA 实体在 rowKey 属性为主键时抛出异常？

Question

我正在使用 JavaEE 构建一个非常简单的 Java 全堆栈应用程序，因此我使用 JSF 和 Prime Faces 6.2 在前端呈现 xthml，在后端使用 EJB、JPA 和 Hibernate 和 postgresql，然而，当我从 Prime Faces 的数据表组件中设置了 rowKey="#{person.id}"。抛出下一个异常。

“00:13:36,307 错误 [io.undertow.request](默认任务 55)UT005023:对/javaee-app/faces/listPersons.xhtml 的异常处理请求:javax.servlet.ServletException ... Caused by :java.lang.NullPointerException"

listPersons.xhtml
Prime Faces DataTable Component(opening tag and its attributes)

<p:dataTable id="persons"
                 value="#{personBean.persons}"
                 var="person"
                 editable="true"
                 rowKey="#{person.id}"
                 selection="#{personBean.personSelected}"
                 selectionMode="single">

The exception thrown that appears when trying to render the page is this.

但是，如果我设置 rowKey="#{person.name}"或什至 rowKey="#{person.email}"而不是 rowKey="#{person.id}"问题就消失了，xthml 页面是正确呈现。

<p:dataTable id="persons"
             value="#{personBean.persons}"
             var="person"
             editable="true"
             rowKey="#{person.name}"
             selection="#{personBean.personSelected}"
             selectionMode="single">

with rowKey="#{person.name}" or rowKey="#{person.email}" xhtml page is rendered correctly"

Postgresql Database person

模型/实体

@Entity
@Table(name = "person")
@NamedQueries({
@NamedQuery(name = "Person.findAll", query = "SELECT p FROM Person p"), 
@NamedQuery(name = "Person.findById", query = "SELECT p FROM Person p 
WHERE p.id = :id")
, @NamedQuery(name = "Person.findByName", query = "SELECT p FROM 
Person p WHERE p.name = :person_name")
, @NamedQuery(name = "Person.findByLastname", query = "SELECT p FROM 
Person p WHERE p.lastname = :lastname")
, @NamedQuery(name = "Person.findByEmail", query = "SELECT p 
FROM Person p WHERE p.email = :email")
, @NamedQuery(name = "Person.findByPhone", query = "SELECT p 
FROM Person p WHERE p.phone = :phone")})
public class Person implements Serializable {
private static final long serialVersionUID = 1L;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;

@Basic(optional = false)
@NotNull
@Size(min = 1, max = 60)
@Column(name = "person_name")
private String name;

@Basic(optional = false)
@NotNull
@Size(min = 1, max = 60)
private String lastname;

@Basic(optional = false)
@NotNull
@Size(min = 1, max = 60)
private String email;

@Size(max = 60)
private String phone;

@OneToMany(mappedBy = "person", fetch = FetchType.EAGER)
private List<Users> users;

public Person() { }

public Person(Integer id) {
    this.id = id;
}

public int getId() {
    return id;
}

public void setId(int id) {
    this.id = id;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public String getLastname() {
    return lastname;
}

public void setLastname(String lastname) {
    this.lastname = lastname;
}


public String getEmail() {
    return email;
}

public void setEmail(String email) {
    this.email = email;
}

public String getPhone() {
    return phone;
}

public void setPhone(String phone) {
    this.phone = phone;
}

public List<Users> getUsers() {
    return users;
}

public void setUsers(List<Users> users) {
    this.users = users;
}

@Override
public int hashCode() {
    int hash = 0;
    hash += (id != null ? id.hashCode() : 0);
    return hash;
}

@Override
public boolean equals(Object object) {
    if (!(object instanceof Person)) {
        return false;
    }
    Person other = (Person) object;
    if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
        return false;
    }
    return true;
}

@Override
public String toString() {
    return "Person [id = " + id + ", name=" + name
            + ", lastName=" + lastname + " email=" + email + ", phone=" + phone + "]";
}

Any idea to solve this problem guys? Thanks in advance

我还添加了应用服务器中生成的错误图像，在我的例子中是 Wildfly 8.2

picture1 Wildfly 8.2

picture2 Wildfly 8.2

Answer 1

id是Integer类型:

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;

当 getter 返回 int 时:

public int getId() {
    return id;
}

更改 getId 以返回整数。