在下面的 JSON
结构中,fileMetaData
参数有不同的类型。 Jackson
抛出异常 com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of com.XXX.XXX.XXX.FILENAME out of START_ARRAY token
。
示例 JSON
负载:
[
{
"fileName": "file_name_1",
"fileMetaData": {
"abcd": "valueabcd",
"xyz": "valuexyz"
}
},
{
"fileName": "file_name_2",
"fileMetaData": [
{
"123": "value123",
"456": "value456"
},
{
"123": "value123-1",
"456": "value456-1"
}
]
},
{
"fileName": "file_name_3",
"fileMetaData": {
"key1": {
"key11": "val11",
"key12": "val22"
},
"key2": "val2"
}
},
{
"fileName": "abc.xyz",
"fileMetaData": null
}
]
如何反序列化?
最佳答案
一般Jackson
将JSON Array
转换为List
,将JSON Object
转换为Map
.在这种情况下,我们可以使用一般的 Object
类型,它将被正确设置。我们只需要检查给定情况下的类型并正确转换为正确的 Java
类型。请参见以下示例:
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.File;
import java.util.List;
import java.util.Map;
public class JsonApp {
public static void main(String[] args) throws Exception {
File jsonFile = new File("./resource/test.json").getAbsoluteFile();
ObjectMapper mapper = new ObjectMapper();
TypeReference<List<Item>> typeReference = new TypeReference<List<Item>>() {
};
List<Item> items = mapper.readValue(jsonFile, typeReference);
items.forEach(item -> {
if (item.isArray()) {
System.out.println("List => " + item.getFileMetaDataAsList());
} else if (item.isObject()) {
System.out.println("Map => " + item.getFileMetaDataAsMap());
}
});
}
}
class Item {
private String fileName;
private Object fileMetaData;
public String getFileName() {
return fileName;
}
public void setFileName(String fileName) {
this.fileName = fileName;
}
public Object getFileMetaData() {
return fileMetaData;
}
public void setFileMetaData(Object fileMetaData) {
this.fileMetaData = fileMetaData;
}
public boolean isObject() {
return this.fileMetaData instanceof Map;
}
public boolean isArray() {
return this.fileMetaData instanceof List;
}
public Map<String, Object> getFileMetaDataAsMap() {
return (Map<String, Object>) this.fileMetaData;
}
public List<Map<String, Object>> getFileMetaDataAsList() {
return (List<Map<String, Object>>) this.fileMetaData;
}
@Override
public String toString() {
return "Item{" +
"fileName='" + fileName + '\'' +
", fileMetaData=" + fileMetaData +
'}';
}
}
对于您的 JSON
负载打印:
Map => {abcd=valueabcd, xyz=valuexyz}
List => [{123=value123, 456=value456}, {123=value123-1, 456=value456-1}]
Map => {key1={key11=val11, key12=val22}, key2=val2}
关于java - 如何使用 jackson (com.fasterxml.jackson) 为相同的 key 使用不一致的 json 结构?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56111575/