java - 从包含文件名的字符串中提取模式

Question

我想从下面的字符串中提取 uid 后缀。我正在尝试模式。但找不到匹配项。

输入:exportDocumentInfo_29510309-5673-4c20-83bd-6d2303c21016-0.txt

uid:29510309-5673-4c20-83bd-6d2303c21016

后缀:0

public class Test {
    public static void main(String[] args) {
        Pattern pattern = Pattern.compile("exportDocumentInfo_*-*.txt");
        String mydata = "exportDocumentInfo_29510309-5673-4c20-83bd-6d2303c21016-0.txt
";

        Matcher matcher = pattern.matcher(mydata);
        if(matcher.matches()) {
            System.out.println(matcher.group(1));
            System.out.println(matcher.group(2));
        }

    }

Answer 1

将每个 * 替换为 (.*)。另外，去掉 "; 之前的换行符，否则程序将无法编译。结果应该类似于这样:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test {
    public static void main(final String[] args) {
        final Pattern pattern = 
                Pattern.compile("exportDocumentInfo_(.*)-(.*).txt");
        final String mydata =
                "exportDocumentInfo_29510309-5673-4c20-83bd-6d2303c21016-0.txt";
        final Matcher matcher = pattern.matcher(mydata);

        if (matcher.matches()) {
            System.out.println(matcher.group(1));
            System.out.println(matcher.group(2));
        }
    }
}

Ideone example