java - 通过java编码的SFTP抛出异常并说无效的绝对URI

Question

Followed this code

我收到这个错误，我在程序中所做的唯一更改是我将参数硬编码为

String  hostName = "122.183.217.133" ; 
String username  = "root";
String password = "something";
String  localFilePath = "C://Sample.jpg";
String  remoteFilePath = "/var/www/html/intranetupload/uploads/Sample.jpg";

Jun 25, 2012 2:52:18 PM org.apache.commons.vfs2.VfsLog info
INFO: Using "C:\DOCUME~1\MEENAK~1.DCK\LOCALS~1\Temp\vfs_cache" as temporary files store.
Exception in thread "main" java.lang.RuntimeException: org.apache.commons.vfs2.FileSystemException: Invalid absolute URI "sftp://root:***@122.183.217.133:22/var/www/html/intranetupload/uploads/Sample1.jpg".
    at sftp.sample.Main.delete(Main.java:120)
    at sftp.sample.Main.main(Main.java:36)
Caused by: org.apache.commons.vfs2.FileSystemException: Invalid absolute URI "sftp://root:***@122.183.217.133:22/var/www/html/intranetupload/uploads/Sample1.jpg".
    at org.apache.commons.vfs2.provider.AbstractOriginatingFileProvider.findFile(AbstractOriginatingFileProvider.java:61)
    at org.apache.commons.vfs2.impl.DefaultFileSystemManager.resolveFile(DefaultFileSystemManager.java:693)
    at org.apache.commons.vfs2.impl.DefaultFileSystemManager.resolveFile(DefaultFileSystemManager.java:621)
    at sftp.sample.Main.delete(Main.java:111)
    ... 1 more
Caused by: org.apache.commons.vfs2.FileSystemException: Expecting / to follow the hostname in URI "sftp://root:***@122.183.217.133:22/var/www/html/intranetupload/uploads/Sample1.jpg".
    at org.apache.commons.vfs2.provider.HostFileNameParser.extractToPath(HostFileNameParser.java:155)
    at org.apache.commons.vfs2.provider.URLFileNameParser.parseUri(URLFileNameParser.java:50)
    at org.apache.commons.vfs2.provider.AbstractFileProvider.parseUri(AbstractFileProvider.java:188)
    at org.apache.commons.vfs2.provider.AbstractOriginatingFileProvider.findFile(AbstractOriginatingFileProvider.java:57)
    ... 4 more  

我没有服务器的域名。我只有一台 ubuntu 机器，它的 IP/用户名和密码是已知的。 我的工作需要删除该远程 Ubuntu 机器中的文件。

你能帮我解决这个错误吗？

Answer 1

解决方法是在调用resolveFile()之前对用户名和密码进行Url编码；

所以如果你需要这样调用:

manager.resolveFile("sftp://sftpuser@Location:Test!@#$%^&*()[]:;@US456564/home57556");

其中用户名为“sftpuser@Location”，密码为“Test!@#$%^&*[]:;:

你只对用户名和密码进行编码，然后像这样调用它:

manager.resolveFile("sftp://sftpuser%40Location:Test!%40%23%24%25%5E%26*%5B%5D%3A%3B@US456564/home57556");

作为 Sting，它可能看起来有点乱，但在调用代码中没有太大问题。