我有一个编码为 1250 的大文件。行只是一个接一个的波兰语单词:
zając
dzieło
kiepsko
etc
我需要以相当快的方式从此文件中随机选择 10 行。我这样做了,但是当我打印这些词时,它们的编码有误 [zaj?c, dzie?o, kiepsko...],我需要 UTF8。所以我更改了我的代码以从文件中读取字节而不仅仅是读取行,所以我的努力最终得到了这段代码:
public List<String> getRandomWordsFromDictionary(int number) {
List<String> randomWords = new ArrayList<String>();
File file = new File("file.txt");
try {
RandomAccessFile raf = new RandomAccessFile(file, "r");
for(int i = 0; i < number; i++) {
Random random = new Random();
int startPosition;
String word;
do {
startPosition = random.nextInt((int)raf.length());
raf.seek(startPosition);
raf.readLine();
word = grabWordFromDictionary(raf);
} while(checkProbability(word));
System.out.println("Word: " + word);
randomWords.add(word);
}
} catch (IOException ioe) {
logger.error(ioe.getMessage(), ioe);
}
return randomWords;
}
private String grabWordFromDictionary(RandomAccessFile raf) throws IOException {
byte[] wordInBytes = new byte[15];
int counter = 0;
byte wordByte;
char wordChar;
String convertedWord;
boolean stop = true;
do {
wordByte = raf.readByte();
wordChar = (char)wordByte;
if(wordChar == '\n' || wordChar == '\r' || wordChar == -1) {
stop = false;
} else {
wordInBytes[counter] = wordByte;
counter++;
}
} while(stop);
if(wordInBytes.length > 0) {
convertedWord = new String(wordInBytes, "UTF8");
return convertedWord;
} else {
return null;
}
}
private boolean checkProbability(String word) {
if(word.length() > MAX_LENGTH_LINE) {
return true;
} else {
double randomDouble = new Random().nextDouble();
double probability = (double) MIN_LENGTH_LINE / word.length();
return probability <= randomDouble;
}
}
但是有一点不对。你能看看这段代码并帮助我吗?也许你看到一些明显的错误但对我来说并不明显?我将不胜感激任何帮助。
最佳答案
你的文件是1250的,所以你需要用1250解码,而不是UTF-8。不过,您可以在解码过程后将其保存为 UTF-8。
Charset w1250 = Charset.forName("Windows-1250");
convertedWord = new String(wordInBytes, w1250);
关于java - 从具有不同编码的文件中使用 RandomAccessFile 读取字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13869263/